获得Java异常的堆栈信息

最新推荐文章于 2024-05-12 17:08:25 发布

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public static String getExceptionStack(Exception e) {
        StackTraceElement[] stackTraceElements = e.getStackTrace();
        String result = e.toString() + "\n";
        for (int index = stackTraceElements.length - 1; index >= 0; --index) {
                result += "at [" + stackTraceElements[index].getClassName() + ",";
                result += stackTraceElements[index].getFileName() + ",";
                result += stackTraceElements[index].getMethodName() + ",";
                result += stackTraceElements[index].getLineNumber() + "]\n";
        }
        return result;
}