指定多个线程按顺序循环执行

yongqi_wang

于 2019-04-03 22:14:11 发布

阅读量539

点赞数 2

CC 4.0 BY-SA版权

分类专栏：个人总结文章标签：信号量

本文链接：https://blog.youkuaiyun.com/yongqi_wang/article/details/89006063

个人总结专栏收录该内容

58 篇文章

订阅专栏

本文介绍了一个使用Java的Semaphore类实现的简单并发控制案例。通过三个线程t1、t2和t3依次输出字符“A”、“B”和“C”，展示了如何利用信号量来协调线程之间的执行顺序。

摘要生成于 C知道，由 DeepSeek-R1 满血版支持，前往体验 >

import java.util.concurrent.Semaphore;
public class test {

    private static Semaphore s1 = new Semaphore(1);
    private static Semaphore s2 = new Semaphore(0);
    private static Semaphore s3 = new Semaphore(0);
    private static int num = 6;
    static Thread t1 = new Thread(new Runnable() {
        private int sum = 0;
        public void run() {
            while (sum < num) {
                try {
                    s1.acquire();
                    System.out.print("A");
                    sum ++;
                } catch (Exception e) {
                    e.printStackTrace();
                }finally {
                    s2.release();
                }
            }
        }
    });
    static  Thread t2 = new Thread(new Runnable() {
        private int sum = 0;
        public void run() {
            while (sum < num) {
                try {
                    s2.acquire();
                    System.out.print("B");
                    sum ++ ;
                } catch (Exception e) {
                    e.printStackTrace();
                }finally {
                    s3.release();
                }
            }
        }
    });
    static Thread t3 = new Thread(new Runnable() {
        private int sum = 0;
        public void run() {
            while (sum < num) {
                try {
                    s3.acquire();
                    System.out.println("C");
                    sum++;
                } catch (Exception e) {
                    e.printStackTrace();
                }finally {
                    s1.release();
                }
            }
        }
    });
}