Strange fuction
TimeLimit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K(Java/Others)Total Submission(s): 767 Accepted Submission(s):588
Problem Description
Now, here is a fuction:
F(x) = 6 * x^7+8*x^6+7*x^3+5*x^2-y*x (0 <= x<=100)
Can you find the minimum value when x is between 0 and 100.
F(x) = 6 * x^7+8*x^6+7*x^3+5*x^2-y*x (0 <= x<=100)
Can you find the minimum value when x is between 0 and 100.
Input
The first line of the input contains aninteger T(1<=T<=100) which means thenumber of test cases. Then T lines follow, each line has only onereal numbers Y.(0 < Y <1e10)
Output
Just the minimum value (accurate up to 4decimal places),when x is between 0 and 100.
Sample Input
2 100200
Sample Output
-74.4291-178.8534
Author
Redow
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#include<math.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
using namespace std;
double g(double x)
{
return42.0*pow(x,6.0)+48.0*pow(x,5.0)+21.0*pow(x,2.0)+10.0*x;
}
double f(double x,double y)
{
return6.0*pow(x,7.0)+8.0*pow(x,6.0)+7.0*pow(x,3.0)+5.0*pow(x,2.0)-x*y;
}
int main(){
int t;
doubley,l,h,mid;
scanf("%d",&t);
while(t--){
scanf("%lf",&y);
if(g(100.0)-y<=0){
printf("%.4lf",f(100.0,y));
printf("1\n");
}
if(g(0.0)-y>=0){
printf("%.4lf",f(0.0,y));
continue;
}
l=0.0;
h=100.0;
while(h-l>1e-8){
mid=(h + l)/2.0;
if(g(mid)-y<0)
l=mid;
else
h=mid;
}
printf("%.4lf\n",f(mid,y));
}
return0;
}