LYY

大数相减 计算n个a相减-Python-未解决a = list(map(int, input().split(" ")))b = (10 ** (a[1]) - 1) / 9c = 0print(b)for x in range(1, a[1]): c += (10 ** x - 1) / 9 # print(c)d = (b - c) * a[0]print(int(d))问题：当n<10时，程序的到结果正常，但当n>10时，程序出现问题：...

import numpy as npn = np.array([ [1,0,0], [0,1,0], [0,0,1], [1,1,1]])print(n.shape[0])print(n.shape[1])得到的结果为由此可得当shape[0]时，得到的是矩阵的行数当shape[1]时，得到的是矩阵的列数...