1001. A+B Format (20)-优快云博客

本文介绍了一个编程问题，即如何计算两个整数a和b的和，并以标准格式输出结果，其中涉及符号处理、数字分组及逗号分隔等细节。

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1001. A+B Format (20)

时间限制
400 ms
内存限制
65536 kB
代码长度限制
16000 B
判题程序
Standard
作者
CHEN, Yue
Calculate a + b and output the sum in standard format – that is, the digits must be separated into groups of three by commas (unless there are less than four digits).

Input

Each input file contains one test case. Each case contains a pair of integers a and b where -1000000 <= a, b <= 1000000. The numbers are separated by a space.

Output

For each test case, you should output the sum of a and b in one line. The sum must be written in the standard format.

Sample Input
-1000000 9
Sample Output
-999,991
提交代码

解题步骤：
1.求和
2.处理符号
3.分离数字–入栈
4.出栈–按位的位置补逗号
提示：别忘了处理和为0的情况

实例代码

#include<iostream>
#include<vector>
#include<cstdio>
using namespace std;
int main()
{
    int a, b, sum;
    cin >> a >> b;
    sum = a + b;
    if (sum <0)
    {
        cout << '-';
        sum = -sum;
    }
    int count = 0;
    vector<int> s;
    if (sum == 0)
    {
        count++;
        s.push_back(sum);
    }
    while (sum != 0)
    {
        count++;//数字个数
        s.push_back(sum % 10);
        sum /= 10;
    }
    for (int i = count - 1; i >= 0; i--)
    {
        if ((i - 2) % 3 == 0 && i != count-1)
        {
            cout << ',' << s[i];
        }
        else cout << s[i];
    }
    system("pause");
    return 0;
}