vector的应用

2.定义vector,放入数字1-52,分别代表各花色的扑克牌.从小到大为黑红梅方,1-K.
随机给四个玩家发3张牌,并打印牌面

#include <iostream>
#include <string>
#include <vector>
#include <sstream>
#include <ctime>
void show(std::vector<int> A)
{
    std::string str;
    std::string num;
    for (size_t i = 0; i < A.size(); i++)
    {
        switch (A[i] % 4)
        {
        case 0:
            str = 4;//4方
            break;
        case 1:
            str = 6;//6黑
            break;
        case 2:
            str = 3;//3红
            break;
        case 3:
            str = 5;//5梅
            break;
        default:
            break;
        }
        switch (A[i] / 4 + 1)
        {
        case 1:
            num = "A";
            break;
        case 11:
            num = "J";
            break;
        case 12:
            num = "Q";
            break;
        case 13:
            num = "K";
            break;
        default:
            num = std::to_string(A[i] / 4 + 1);
            break;
        }
        std::cout << str << " " << num << std::endl;
    }
    std::cout << std::endl;
}

void vectorDemo() 
{
    srand((unsigned)time(NULL));
    std::vector<int> vec;
    for (size_t i = 1; i < 53; i++)
    {
        vec.push_back(i);
    }
    std::vector<int> A, B, C, D;
    int k, count = 0;
    for (size_t i = 0; count<4;)
    {
        k = rand() % vec.size() + 1;
        switch (count)
        {
        case 0:
            A.push_back(vec[k]);
            vec.erase(find(vec.begin(), vec.end(), vec[k]));
            break;
        case 1:
            B.push_back(vec[k]);
            vec.erase(find(vec.begin(), vec.end(), vec[k]));
            break;
        case 2:
            C.push_back(vec[k]);
            vec.erase(find(vec.begin(), vec.end(), vec[k]));
            break;
        case 3:
            D.push_back(vec[k]);
            vec.erase(find(vec.begin(), vec.end(), vec[k]));
            break;
        default:
            break;
        }
        i++;
        if (i == 3)
        {
            i = 0;
            count++;
        }
    }
    show(A);
    show(B);
    show(C);
    show(D);
}

还没有思路,被这容器搞得有点蒙