9 |
N |
9 |
|
|
|
|
|
|
|
|
|
8 |
O |
8 |
|
|
|
|
|
|
|
|
|
7 |
I |
7 |
|
|
|
|
|
|
|
|
|
6 |
T |
6 |
|
|
|
|
|
|
|
|
|
5 |
N |
5 |
|
|
|
|
|
|
|
|
|
4 |
E |
4 |
3 |
|
|
|
|
|
|
|
|
3 |
T |
3 |
4 |
5 |
|
|
|
|
|
|
|
2 |
n |
2 |
3 |
4 |
5 |
|
|
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|
|
1 |
I |
1 |
2 |
3 |
4 |
|
|
|
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|
|
0 |
# |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
|
|
# |
e |
x |
e |
c |
u |
t |
i |
o |
n |
|
|
0 |
1 |
2 |
3 |
4 |
5 |
6 |
7 |
8 |
9 |
Source = intention
Target = execution
D[0][1] = d[0][0]+del[source 0] = 1 (如何把 I 编程 epson)
D[1][0] = d[0][0]+ins[target 0] = 1 (如何把 Epson 编程 e)
D[1][1] = d[0][1]+ins[target 0] = 2 (Epson的基础上,把epson变成e)
= d[1][0]+del[source 0] = 2 (在 epson已经变成e的基础上,把i变成e)
=d[0][0]+subst[] = 2 (在空变成空的前提下,如何把i变成e?就是先删除i,然后插入e)、
下面类推。