select timediff('23:40:00', ' 18:30:00'); -- 两时间相减
SELECT substring( timediff('23:40:00', ' 18:30:00'),1,5) ----“05:10”相减返回小时:分钟
SELECT substring( timediff('23:40:00', ' 18:30:00'),1,5) ----“05:10”相减返回小时:分钟
select datediff('2008-08-08', '2008-08-01'); -- 7 -----两日期相减
select TO_DAYS('2008-09-08')-TO_DAYS('2008-08-08') -----两日期相减
SELECT substring( '2009-06-17 10:00:00', 1, 10 ) ----从datetime中提取“日期”
资源来源:http://blog.youkuaiyun.com/yuxiayiji/article/details/7480785