Given a binary tree, find its minimum depth.
The minimum depth is the number of nodes along the shortest path from the root node down to the nearest leaf node.
Note: A leaf is a node with no children.
Example:
Given binary tree [3,9,20,null,null,15,7],
3
/ \
9 20
/ \
15 7
return its minimum depth = 2.
代码:
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
int minDepth(TreeNode* root) {
if(root == NULL)
return 0;
if(root->left == NULL || root->right == NULL) //这种方法比较快
return max(minDepth(root->left), minDepth(root->right))+1;
return min(minDepth(root->left), minDepth(root->right))+1;
}
};
用时:


本文介绍了一种求解二叉树最小深度的有效算法。通过递归方式遍历树的左右子节点,寻找从根节点到最近叶子节点的最短路径。文章提供了完整的C++实现代码,并针对特殊情况进行了优化。
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