uva 146 Problem Set Volumes->Volumes 1 的146题

本文介绍如何使用STL中的next_permutation函数来生成给定字符串的下一个字典序字符串。通过实例演示了如何判断是否还有下一个排列,并给出了完整的代码实现。

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//学习了新东西STL之全排列函数。
//next_permutation(s,s+len) 执行一次函数就生成下一个字典序字符串。如果没有下一个就返回false。

//这道题要求生成给出字符串的下一个字典序字符串。如果没有就输出 No Successor.


#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
char s[60];
int main()
{
    while(scanf("%s",s)&&s[0]!='#')
    {
        int len = strlen( s);
        if(next_permutation(s,s+len))
        printf("%s\n",s);
        else printf("No Successor\n");
    }
    return 0;
}

ID Codes

Time Limit: 1000MS Memory limit: 10000K

题目描述

It is 2084 and the year of Big Brother has finally arrived, albeit a century late. In order to exercise greater control over its citizens and thereby to counter a chronic breakdown in law and order, the Government decides on a radical measure--all citizens are to have a tiny microcomputer surgically implanted in their left wrists. This computer will contains all sorts of personal information as well as a transmitter which will allow people's movements to be logged and monitored by a central computer. (A desirable side effect of this process is that it will shorten the dole queue for plastic surgeons.) 

An essential component of each computer will be a unique identification code, consisting of up to 50 characters drawn from the 26 lower case letters. The set of characters for any given code is chosen somewhat haphazardly. The complicated way in which the code is imprinted into the chip makes it much easier for the manufacturer to produce codes which are rearrangements of other codes than to produce new codes with a different selection of letters. Thus, once a set of letters has been chosen all possible codes derivable from it are used before changing the set. 

For example, suppose it is decided that a code will contain exactly 3 occurrences of `a', 2 of `b' and 1 of `c', then three of the allowable 60 codes under these conditions are: 

abaabc 
abaacb 
ababac 

These three codes are listed from top to bottom in alphabetic order. Among all codes generated with this set of characters, these codes appear consecutively in this order. 

Write a program to assist in the issuing of these identification codes. Your program will accept a sequence of no more than 50 lower case letters (which may contain repeated characters) and print the successor code if one exists or the message `No Successor' if the given code is the last in the sequence for that set of characters.

输入

Input will consist of a series of lines each containing a string representing a code. The entire file will be terminated by a line consisting of a single #.

输出

Output will consist of one line for each code read containing the successor code or the words 'No Successor'

示例输入

abaacb
cbbaa
#

示例输出

ababac
No Successor

### Docker `--volumes-from` 参数详解 #### 功能描述 `--volumes-from` 参数用于让新创建的容器挂载另一个已存在容器中的卷。这使得多个容器可以共享同一个数据存储位置,方便实现跨容器的数据同步和共享[^1]。 #### 基本语法 ```bash docker run -it --name new_container_name --volumes-from source_container_id image_name command ``` 其中: - `-it`: 交互模式启动容器; - `new_container_name`: 新建容器的名字; - `source_container_id`: 已有容器ID或名称,作为源容器提供要挂载的卷; - `image_name`: 要使用的镜像名; - `command`: 启动后的执行指令。 #### 示例演示 假设有一个名为 `data-container` 的容器已经包含了某些重要文件夹 `/var/lib/mysql` ,现在希望另外两个新的容器也能够访问这个路径下的内容: ```bash # 创建第一个依赖于 data-container 卷的新容器 docker run -d --name db_backup_01 --volumes-from data-container mysql:latest mysqldump ... # 再次创建第二个同样依赖该卷的新容器 docker run -ti --rm --volumes-from data-container centos bash ``` 上述例子展示了如何通过指定 `--volumes-from data-container` 来使其他容器继承来自 `data-container` 中定义好的任何卷设置。 #### 只读权限控制 如果只想让目标容器以只读方式访问某个特定卷,则可以在命令后面加上 `:ro` 标志位: ```bash docker run --volumes-from existing_container:ro ... ``` 这样做的好处是可以防止意外修改原始数据的同时保持必要的资源共享能力[^2]。 #### 解决方案与注意事项 当遇到无法正常工作的情况时,可尝试以下方法排查并解决问- **确认源容器状态**:确保被引用的源容器处于运行状态;停止状态下仍能成功加载卷但可能影响性能。 - **检查命名冲突**:避免不同容器间出现相同名字引起混淆错误。 - **清理残留资源**:删除不再需要的老化容器以免干扰最新实例间的通信连接。 - **更新客户端版本**:对于较老版Docker CLI来说部分特性支持有限,建议升级到稳定发行版再试一次操作流程。 #### 替代工具推荐 考虑到复杂场景下手动管理多层嵌套关系容易出错,官方推出了更高级别的组合式应用编排框架——Docker Compose 。它允许用户在一个YAML配置文档里清晰地表达整个应用程序所需的所有组件和服务,并简化了一键部署过程[^3]。
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