Given a nested list of integers, implement an iterator to flatten it.
Each element is either an integer, or a list -- whose elements may also be integers or other lists.
Example 1:
Given the list [[1,1],2,[1,1]],
By calling next repeatedly until hasNext returns false, the order of elements returned by
next should be: [1,1,2,1,1].
Example 2:
Given the list [1,[4,[6]]],
By calling next repeatedly until hasNext returns false, the order of elements returned by
next should be: [1,4,6].
这个题不难,有想法就好实现,用队列来解决。
/**
* // This is the interface that allows for creating nested lists.
* // You should not implement it, or speculate about its implementation
* public interface NestedInteger {
*
* // @return true if this NestedInteger holds a single integer, rather than a nested list.
* public boolean isInteger();
*
* // @return the single integer that this NestedInteger holds, if it holds a single integer
* // Return null if this NestedInteger holds a nested list
* public Integer getInteger();
*
* // @return the nested list that this NestedInteger holds, if it holds a nested list
* // Return null if this NestedInteger holds a single integer
* public List<NestedInteger> getList();
* }
*/
public class NestedIterator implements Iterator<Integer> {
Deque<Integer> queue=new ArrayDeque<Integer>();
public void putIntoQueue(List<NestedInteger> list){
for(int i=0;i<list.size();i++){
if(list.get(i).isInteger()){
queue.offer(list.get(i).getInteger());
}else{
putIntoQueue(list.get(i).getList());
}
}
}
public NestedIterator(List<NestedInteger> nestedList) {
putIntoQueue(nestedList);
}
public Integer next() {
return queue.poll();
}
public boolean hasNext() {
return queue.size()>0;
}
}
/**
* Your NestedIterator object will be instantiated and called as such:
* NestedIterator i = new NestedIterator(nestedList);
* while (i.hasNext()) v[f()] = i.next();
*/
本文介绍了一种使用队列实现的嵌套列表迭代器,该迭代器可以将嵌套的整数列表扁平化,并按顺序返回所有元素。通过递归地检查每个元素并将其放入队列中,确保了元素的正确输出顺序。
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