SDUTOJ 3035 你猜我猜不猜你猜不猜

最新推荐文章于 2021-08-22 23:40:10 发布

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本文深入探讨了游戏开发领域的核心技术，包括游戏引擎、动画制作、图像处理、音视频编解码等，并结合AI音视频处理技术，如语义识别、语音识别、AR等，展示了如何在游戏开发中应用这些先进技术，以提升用户体验和游戏创新。

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你猜我猜不猜你猜不猜

Time Limit: 2000ms Memory limit: 65536K 有疑问？点这里^_^

题目描述

In the past 39th annual ACM international collegiate programming contest in Beijing station in Asia that Triple_S sent by our school team won the SDUT in Reginal bronze 11. At the same time,the team’s name is cray which is to let the host after reading the wrong three times, still missed a word to read. But zhuhu gave a high evaluation to the team.

As the creator of this team, I want to say is, in fact I was reminded of a game which is named ”ni cai wo cai bu cai ni cai bu cai wo cai bu cai”, may be the teacher didn\'t remember it. The name is just due to a conversation with a girl, so the origin is simple.

A：Why are you so diao?

B:Ni cai.

A:Ni cai wo cai bu cai.

B:Ni cai wo cai bu cai ni cai bu cai.

A:Ni cai wo cai bu cai ni cai bu cai wo cai bu cai.

Then do you know the content of their first conversation X？OK，in order to avoid the mle , RE professionals will popularize related knowledge for you . Please seize this chance!

The operation is very simple, only need to output the first letter of each word .For example , You can substitute N for Ni . Next, I\'ll demonstrate specific operation steps

输入

For everytestcase , each line of input a Character , said A or B .

Then enter an Integer X (0<=X<=10^5), said the figure’s the first X words.

输出

Output the words.

示例输入

A 2
A 3
B 3

示例输出

Ncwcbc
Ncwcbcncbcwcbc
Ncwcbcncbcwcbcncbc

提示

输入请用 cin

来源

Flyfire

示例程序

#include<iostream>
#include<algorithm>
#include<stdio.h>
#include<string.h>
#include<string>
#include<stdlib.h>

using namespace std;

int main()
{
char c[100];
while(cin >> c)
{
string b,a;
int x;
if(c[0] == 'A')
{
scanf("%d",&x);
if(x == 1)
{
cout << "Waysd" << endl;
}
else
{
if(x == 2)
{
cout << "Ncwcbc" << endl;
}
else
{
cout << "Ncwcbc";
for(int i=3; i<=x; i++)
{
cout << "ncbcwcbc";
}
cout << endl;
}

}
}
else if(c[0] == 'B')
{
scanf("%d",&x);
if(x == 1)
{
cout << "Nc" << endl;
}
else
{
cout << "Nc";
for(int j=2; j<=x; j++)
{
cout << "wcbcncbc";
}
cout << endl;
}

}
}
return 0;
}