C语言将整形数值存入指定的内存段中的方法

【错误的做法】

下面的做法实际上是将数值1234按照字符串”1234“的方式存入char数组buf的。

int data = 1234;
char buf[10];
sprintf(buf, "%d", data);

【正确的做法】

int data = 1234;
int data_big_endian = htobe32(data); // if big or small endian is considered
char buf[10];
memcpy((void)buf, &data_big_endian, 4);

【小例子】

#include <iostream>
using namespace std;

#include <string.h>
#include <inttypes.h>
#include <endian.h>

int main(int argc, char * argv[]) {
	unsigned char * buff = new unsigned char[10];

	int a = 23423;
	int b = 62365;

	cout << a << endl;
	cout << b << endl;
	cout << endl;

	uint16_t a_be = htobe16(a);
	uint16_t b_be = htobe16(b);

	cout << a_be << endl;
	cout << b_be << endl;
	cout <&