select to_char(to_date('201908','yyyymm')+(rownum-1),'dd') DAY_ID
from dual
connect by rownum<=to_number(to_char(last_day(to_date('201908','yyyymm')),'dd'))
要显示每月的每一天的数据,哪怕那天没有数据也要显示出来日期
最新推荐文章于 2023-09-11 10:56:31 发布
select to_char(to_date('201908','yyyymm')+(rownum-1),'dd') DAY_ID
from dual
connect by rownum<=to_number(to_char(last_day(to_date('201908','yyyymm')),'dd'))