Left join:即左连接,是以左表为基础,根据ON后给出的两表的条件将两表连接起来。结果会将左表所有的查询信息列出,而右表只列出ON后条件与左表满足的部分。左连接全称为左外连接,是外连接的一种。
Right join:即右连接,是以右表为基础,根据ON后给出的两表的条件将两表连接起来。结果会将右表所有的查询信息列出,而左表只列出ON后条件与右表满足的部分。右连接全称为右外连接,是外连接的一种。
Inner join:即内连接,同时将两表作为参考对象,根据ON后给出的两表的条件将两表连接起来。结果则是两表同时满足ON后的条件的部分才会列出。
COUNT(*) 函数返回在给定的选择中被选的行数。
UNION 操作符用于合并两个或多个 SELECT 语句的结果集。UNION 内部的 SELECT 语句必须拥有相同数量的列。列也必须拥有相似的数据类型。同时,每条 SELECT 语句中的列的顺序必须相同。不会合并重复值,默认地,UNION 操作符选取不同的值。如果允许重复的值,请使用 UNION ALL。
UNION ALL 命令和 UNION 命令几乎是等效的,不过 UNION ALL 命令会列出所有的值
在表中,一个列可能会包含多个重复值,有时您也许希望仅仅列出不同(distinct)的值。
DISTINCT 关键词用于返回唯一不同的值。
LAST() 函数返回指定的列中最后一个记录的值。
HAVING语句通常与GROUP BY语句联合使用,用来过滤由GROUP BY语句返回的记录集。HAVING语句的存在弥补了WHERE关键字不能与聚合函数联合使用的不足
1.自行添加测试数据
2.查询平均成绩大于60分的同学的学号和平均成绩;
1 2 3 | SELECT t1.sid, AVG (t2.number) FROM student t1 LEFT JOIN score t2 ON t1.sid=t2.student_id GROUP BY t1.sid HAVING AVG (t2.number)>60; |
3.查询所有同学的学号、姓名、选课数、总成绩;
1 2 3 4 5 | SELECT t1.sid,t1.sname,t2.temp1,t3.temp2 FROM student t1,( SELECT student_id, COUNT (sid) temp1 FROM score GROUP BY student_id) t2, ( SELECT student_id, SUM (number) temp2 FROM score GROUP BY student_id) t3 WHERE t1.sid=t2.student_id AND t1.sid=t3.student_id; #较复杂,有难度 |
4.查询姓“李”的老师的个数;
1 2 3 | SELECT COUNT (tid) FROM teacher WHERE tname LIKE '李%' ; |
5.查询没学过“叶平”老师课的同学的学号、姓名;
1 2 3 4 5 6 7 8 9 10 11 12 13 14 | SELECT t1.`sid`,t1.`sname` FROM student t1 WHERE t1.`sid` NOT IN ( SELECT student_id FROM score WHERE course_id IN ( SELECT t2.cid FROM teacher t1 LEFT JOIN course t2 ON t1.`tid`=t2.`teacher_id` WHERE t1.tname= '叶平' ORDER BY t2.`cid`)); #子句 SELECT student_id FROM score WHERE course_id IN ( SELECT t2.cid FROM teacher t1 LEFT JOIN course t2 ON t1.`tid`=t2.`teacher_id` WHERE t1.tname= '叶平' ORDER BY t2.`cid`);<br>#较复杂 |
6.查询学过“001”并且也学过编号“002”课程的同学的学号、姓名;
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 | #方法1 SELECT t1.`student_id`,t2.`sname` FROM score t1 LEFT JOIN student t2 ON t1.`student_id`=t2.`sid` WHERE course_id=1 UNION ALL SELECT t1.`student_id`,t2.`sname` FROM score t1 LEFT JOIN student t2 ON t1.`student_id`=t2.`sid` WHERE course_id=2; #方法2 SELECT t1.sid,t1.sname FROM ( SELECT t1.`student_id` sid,t2.`sname` sname FROM score t1 LEFT JOIN student t2 ON t1.`student_id`=t2.`sid` WHERE course_id=1 UNION ALL SELECT t1.`student_id`,t2.`sname` FROM score t1 LEFT JOIN student t2 ON t1.`student_id`=t2.`sid` WHERE course_id=2) t1 GROUP BY t1.sid HAVING COUNT (*)>1; |
7.查询学过“叶平”老师所教的所有课的同学的学号、姓名;
1 2 3 4 5 6 7 8 9 10 | SELECT t1.`student_id`,t2.`sname` FROM score t1 LEFT JOIN student t2 ON t1.`student_id`=t2.`sid` WHERE t1.`course_id` IN ( SELECT t2.cid FROM teacher t1 LEFT JOIN course t2 ON t1.`tid`=t2.`teacher_id` WHERE t1.tname= '叶平' ORDER BY t2.`cid`); #子句 SELECT t2.cid FROM teacher t1 LEFT JOIN course t2 ON t1.`tid`=t2.`teacher_id` WHERE t1.tname= '叶平' ORDER BY t2.`cid`; |
8.查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名;
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 | #子句1 SELECT number FROM score WHERE course_id=2; #子句2 SELECT number FROM score t1 WHERE t1.`course_id`=1; #总语句 SELECT t3.`sid`,t3.`sname` FROM ( SELECT student_id,number FROM score WHERE course_id=2) t1,( SELECT student_id,number FROM score WHERE course_id=1) t2,student t3 WHERE t1.student_id=t3.sid AND t2.student_id=t3.sid AND t1.number<t2.number; |
9.查询有课程成绩小于60分的同学的学号、姓名;
1 2 3 4 5 6 7 8 9 | #方法1 SELECT DISTINCT t1.student_id,t2.`sname` FROM score t1 LEFT JOIN student t2 ON t1.`student_id`=t2.`sid` WHERE t1.number<60; #方法2 SELECT t1.sid,t1.sname FROM student t1,( SELECT student_id FROM score WHERE number<60 GROUP BY student_id) t2 WHERE t1.sid=t2.student_id; |
10.查询没有学全所有课的同学的学号、姓名;
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 | #总语句 SELECT sid,sname FROM student WHERE sid NOT IN ( SELECT student_id FROM score GROUP BY student_id HAVING COUNT (course_id)=( SELECT COUNT (cid) FROM course)); #子句 SELECT sid,sname FROM student WHERE sid NOT IN (); #子句:学全了的学生编号 SELECT student_id FROM score GROUP BY student_id HAVING COUNT (course_id)=( SELECT COUNT (cid) FROM course); #子句:课程的总数 SELECT COUNT (cid) FROM course; |
11.查询至少有一门课与学号为“001”的同学所学相同的同学的学号和姓名;
1 2 3 4 5 6 7 8 9 10 11 | #总语句 SELECT DISTINCT t1.student_id,t2.`sname` FROM score t1 LEFT JOIN student t2 ON t1.`student_id`=t2.`sid` WHERE course_id IN ( SELECT course_id FROM score WHERE student_id=1); #子句:学号1所选所有课程 SELECT course_id FROM score WHERE student_id=1 |
首先还是介绍一下这三个的定义
Left join:即左连接,是以左表为基础,根据ON后给出的两表的条件将两表连接起来。结果会将左表所有的查询信息列出,而右表只列出ON后条件与左表满足的部分。左连接全称为左外连接,是外连接的一种。
Right join:即右连接,是以右表为基础,根据ON后给出的两表的条件将两表连接起来。结果会将右表所有的查询信息列出,而左表只列出ON后条件与右表满足的部分。右连接全称为右外连接,是外连接的一种。
Inner join:即内连接,同时将两表作为参考对象,根据ON后给出的两表的条件将两表连接起来。结果则是两表同时满足ON后的条件的部分才会列出。
MySQL中没有全外连接,所以这里没做解释了。
1.自行添加测试数据
2.查询平均成绩大于60分的同学的学号和平均成绩;
1 2 3 | SELECT t1.sid, AVG (t2.number) FROM student t1 LEFT JOIN score t2 ON t1.sid=t2.student_id GROUP BY t1.sid HAVING AVG (t2.number)>60; |
3.查询所有同学的学号、姓名、选课数、总成绩;
1 2 3 4 5 | SELECT t1.sid,t1.sname,t2.temp1,t3.temp2 FROM student t1,( SELECT student_id, COUNT (sid) temp1 FROM score GROUP BY student_id) t2, ( SELECT student_id, SUM (number) temp2 FROM score GROUP BY student_id) t3 WHERE t1.sid=t2.student_id AND t1.sid=t3.student_id; #较复杂,有难度 |
4.查询姓“李”的老师的个数;
1 2 3 | SELECT COUNT (tid) FROM teacher WHERE tname LIKE '李%' ; |
5.查询没学过“叶平”老师课的同学的学号、姓名;
1 2 3 4 5 6 7 8 9 10 11 12 13 14 | SELECT t1.`sid`,t1.`sname` FROM student t1 WHERE t1.`sid` NOT IN ( SELECT student_id FROM score WHERE course_id IN ( SELECT t2.cid FROM teacher t1 LEFT JOIN course t2 ON t1.`tid`=t2.`teacher_id` WHERE t1.tname= '叶平' ORDER BY t2.`cid`)); #子句 SELECT student_id FROM score WHERE course_id IN ( SELECT t2.cid FROM teacher t1 LEFT JOIN course t2 ON t1.`tid`=t2.`teacher_id` WHERE t1.tname= '叶平' ORDER BY t2.`cid`);<br>#较复杂 |
6.查询学过“001”并且也学过编号“002”课程的同学的学号、姓名;
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 | #方法1 SELECT t1.`student_id`,t2.`sname` FROM score t1 LEFT JOIN student t2 ON t1.`student_id`=t2.`sid` WHERE course_id=1 UNION ALL SELECT t1.`student_id`,t2.`sname` FROM score t1 LEFT JOIN student t2 ON t1.`student_id`=t2.`sid` WHERE course_id=2; #方法2 SELECT t1.sid,t1.sname FROM ( SELECT t1.`student_id` sid,t2.`sname` sname FROM score t1 LEFT JOIN student t2 ON t1.`student_id`=t2.`sid` WHERE course_id=1 UNION ALL SELECT t1.`student_id`,t2.`sname` FROM score t1 LEFT JOIN student t2 ON t1.`student_id`=t2.`sid` WHERE course_id=2) t1 GROUP BY t1.sid HAVING COUNT (*)>1; |
7.查询学过“叶平”老师所教的所有课的同学的学号、姓名;
1 2 3 4 5 6 7 8 9 10 | SELECT t1.`student_id`,t2.`sname` FROM score t1 LEFT JOIN student t2 ON t1.`student_id`=t2.`sid` WHERE t1.`course_id` IN ( SELECT t2.cid FROM teacher t1 LEFT JOIN course t2 ON t1.`tid`=t2.`teacher_id` WHERE t1.tname= '叶平' ORDER BY t2.`cid`); #子句 SELECT t2.cid FROM teacher t1 LEFT JOIN course t2 ON t1.`tid`=t2.`teacher_id` WHERE t1.tname= '叶平' ORDER BY t2.`cid`; |
8.查询课程编号“002”的成绩比课程编号“001”课程低的所有同学的学号、姓名;
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 | #子句1 SELECT number FROM score WHERE course_id=2; #子句2 SELECT number FROM score t1 WHERE t1.`course_id`=1; #总语句 SELECT t3.`sid`,t3.`sname` FROM ( SELECT student_id,number FROM score WHERE course_id=2) t1,( SELECT student_id,number FROM score WHERE course_id=1) t2,student t3 WHERE t1.student_id=t3.sid AND t2.student_id=t3.sid AND t1.number<t2.number; |
9.查询有课程成绩小于60分的同学的学号、姓名;
1 2 3 4 5 6 7 8 9 | #方法1 SELECT DISTINCT t1.student_id,t2.`sname` FROM score t1 LEFT JOIN student t2 ON t1.`student_id`=t2.`sid` WHERE t1.number<60; #方法2 SELECT t1.sid,t1.sname FROM student t1,( SELECT student_id FROM score WHERE number<60 GROUP BY student_id) t2 WHERE t1.sid=t2.student_id; |
10.查询没有学全所有课的同学的学号、姓名;
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 | #总语句 SELECT sid,sname FROM student WHERE sid NOT IN ( SELECT student_id FROM score GROUP BY student_id HAVING COUNT (course_id)=( SELECT COUNT (cid) FROM course)); #子句 SELECT sid,sname FROM student WHERE sid NOT IN (); #子句:学全了的学生编号 SELECT student_id FROM score GROUP BY student_id HAVING COUNT (course_id)=( SELECT COUNT (cid) FROM course); #子句:课程的总数 SELECT COUNT (cid) FROM course; |
11.查询至少有一门课与学号为“001”的同学所学相同的同学的学号和姓名;
1 2 3 4 5 6 7 8 9 10 11 | #总语句 SELECT DISTINCT t1.student_id,t2.`sname` FROM score t1 LEFT JOIN student t2 ON t1.`student_id`=t2.`sid` WHERE course_id IN ( SELECT course_id FROM score WHERE student_id=1); #子句:学号1所选所有课程 SELECT course_id FROM score WHERE student_id=1 |