在研究 Platinum 的 dlna, 其中实现的操作 g_dlna_ctrl_point = (PLT_CtrlPointReference)new PLT_CtrlPoint(); 但是从来不做 delete 操作
当时一直很奇怪,后面仔细看了下 PLT_CtrlPointReference 的实现,原来它实现了一种机制,类似于java语言的对象引用,如果一个对象没有引用了,就会自动释放。
PLT_CtrlPointReference 因为上在 C++ 语言上实现了,巧妙的使用了 析构 函数的应用
先上代码,我把 PLT_CtrlPointReference 的实现简单整理了下,应该可以在各种平台编译测试
typedef unsigned int NPT_Cardinal;
template <typename T>
class NPT_Reference
{
public:
// constructors and destructor
NPT_Reference() : m_Object(NULL), m_Counter(NULL) {}
explicit NPT_Reference(T* object, bool thread_safe = true) :
m_Object(object),
m_Counter(object?new NPT_Cardinal(1):NULL){}
NPT_Reference(const NPT_Reference<T>& ref) :
m_Object(ref.m_Object), m_Counter(ref.m_Counter){
if (m_Counter) ++(*m_Counter);
}
// this methods should be private, but this causes a problem on some
// compilers, because we need this function in order to implement
// the cast operator operator NPT_Reference<U>() below, which would
// have to be marked as a friend, and friend declarations with the
// same class name confuses some compilers
NPT_Reference(T* object, NPT_Cardinal* counter) :
m_Object(object), m_Counter(counter) {
if (m_Counter) ++(*m_Counter);
}
~NPT_Reference() {
Release();
}
// overloaded operators
NPT_Reference<T>& operator=(const NPT_Reference<T>& ref) {
if (this != &ref) {
Release();
m_Object = ref.m_Object;
m_Counter = ref.m_Counter;
if (m_Counter) ++(*m_Counter);
}
return *this;
}
NPT_Reference<T>& operator=(T* object) {
Release();
m_Object = object;
m_Counter = object?new NPT_Cardinal(1):NULL;
return *this;
}
T& operator*() const { return *m_Object; }
T* operator->() const { return m_Object; }
bool operator==(const NPT_Reference<T>& ref) const {
return m_Object == ref.m_Object;
}
bool operator!=(const NPT_Reference<T>& ref) const {
return m_Object != ref.m_Object;
}
// overloaded cast operators
template <typename U> operator NPT_Reference<U>() {
return NPT_Reference<U>(m_Object, m_Counter);
}
// methods
/**
* Returns the naked pointer value.
*/
T* AsPointer() const { return m_Object; }
/**
* Returns the reference counter value.
*/
NPT_Cardinal GetCounter() const { return *m_Counter; }
/**
* Returns whether this references a NULL object.
*/
bool IsNull() const { return m_Object == NULL; }
/**
* Detach the reference from the shared object.
* The reference count is decremented, but the object is not deleted if the
* reference count becomes 0.
* After the method returns, this reference does not point to any shared object.
*/
void Detach() {
Release(true);
}
private:
// methods
void Release(bool detach_only = false) {
bool last_reference = false;
if (m_Counter && --(*m_Counter) == 0) {
delete m_Counter;
if (!detach_only) delete m_Object;
last_reference = true;
}
m_Counter = NULL;
m_Object = NULL;
}
// members
T* m_Object;
NPT_Cardinal* m_Counter;
};
class PLT_CtrlPoint
{
public:
PLT_CtrlPoint(){printf("create\n");};
~PLT_CtrlPoint(){printf("destroy\n");};
};
接下来,我们做测试
typedef NPT_Reference<PLT_CtrlPoint> PLT_CtrlPointReference;
static void test(void)
{
PLT_CtrlPointReference g_dlna_ctrl_point;
g_dlna_ctrl_point = (PLT_CtrlPointReference)new PLT_CtrlPoint();
}
int _tmain(int argc, _TCHAR* argv[])
{
test();
return 0;
}
我们看到,g_dlna_ctrl_point 进行了 new 操作但是没有进行 delete 操作
但是测试的结果是:
destroy 打印出来了
这是因为 g_dlna_ctrl_point 是局部对象,走过了 test() 函数的生存期后,会自动调用 g_dlna_ctrl_point 对象的析构函数,然后引用计数器减1,发现引用计数器为 0 的话,就真正delete 对象
我们再来一个测试
PLT_CtrlPointReference g_dlna_ctrl_point;
static void test(void)
{
g_dlna_ctrl_point = (PLT_CtrlPointReference)new PLT_CtrlPoint();
}
int _tmain(int argc, _TCHAR* argv[])
{
test();
return 0;
}
g_dlna_ctrl_point 现在是全局的了,可见 调用完 test() 函数后,没有进行释放操作
这个时候,我加上 g_dlna_ctrl_point = NULL; 操作,见下面代码
PLT_CtrlPointReference g_dlna_ctrl_point;
static void test(void)
{
g_dlna_ctrl_point = (PLT_CtrlPointReference)new PLT_CtrlPoint();
}
int _tmain(int argc, _TCHAR* argv[])
{
test();
g_dlna_ctrl_point = NULL;
return 0;
}
这个时候可看到:
destroy 被打印出来了
这样,局部的对象,不需要的时候,不需要理会,它自己会消失
全局的对象,不需要的时候,赋值为 NULL 或者是其它的值,类似java的机制,那么这个对象就消失了
了解了这些,再分析这些代码,就清楚了