向函数传递类对象：

测试代码：

#include<iostream>

using namespace std;

 

 

class myclass{

       int i;

public:

       myclass(int x){i=x;cout<<"have make "<<i<<endl;}

       ~myclass(){cout<<"have del "<<i<<endl;}

       void set(int x){i=x;}

       int get(){return i;}

};

 

void fun(myclass x)

{

       x.set(100);

       cout<<"in function i is "<<x.get()<<endl;

}

 

int main()

{

       myclass a(1);

       cout<<"in main i is "<<a.get()<<endl;

       fun(a);

       cout<<"in main i is "<<a.get()<<endl;

       return 0;

}

 

测试结果：

have make 1

in main i is 1

in function i is 100

have del 100

in main i is 1

have del 1

Press any key to continue

 

由此可见，在向函数传递类对象的时候，拷贝类对象时未进行构造函数，离开函数时却进行了析构函数！