#include<cstdio>
int main()
{
int c,t,f;
scanf("%d",&c);
double sum = 0;
for(int j = 0;j < c;++j)
{
sum = 0;
f= 1;
scanf("%d",&t);
for(int i = 1;i<=t;++i)
{
sum += 1/double((i*f));
f *= -1;
}
printf("%.2f\n",sum);
}
}
hdu_2011多项式求和
最新推荐文章于 2020-06-19 12:19:58 发布