题目
Merge two sorted linked lists and return it as a new list. The new list should be made by splicing together the nodes of the first two lists.
原地合并两个已经排序号的链。
代码:
/*******************************************************************
struct ListNode {
int val;
ListNode *next;
ListNode(int x) : val(x), next(NULL) {}
};
*******************************************************************/
class Solution {
public:
ListNode *mergeTwoLists(ListNode *l1, ListNode *l2) {
ListNode *head=NULL,*ps; //新的头,新链已经操作到的位置
if(l1==NULL)
return l2;
if(l2==NULL)
return l1;
if(l1->val<l2->val) //获取新头
{
head=l1;
l1=l1->next;
}
else
{
head=l2;
l2=l2->next;
}
ps=head;
while(l1!=NULL||l2!=NULL) //合并
{
if(l1==NULL)
{
ps->next=l2;
break;
}
if(l2==NULL)
{
ps->next=l1;
break;
}
if(l1->val<l2->val)
{
ps->next=l1;
ps=l1;
l1=l1->next;
}
else
{
ps->next=l2;
ps=l2;
l2=l2->next;
}
}
return head;
}
};