Intel® 64 and IA-32 Architectures:0001-前言

本文深入解读了Intel®64和IA-32架构软件开发者手册,包括基本架构、指令集参考和系统编程指南等五卷内容,指导开发者在评估设计需求时如何有效利用这些资源。

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The Intel® 64 and IA-32 Architectures Software Developer's Manual consists of five volumes: Basic Architecture, Order Number 253665; Instruction Set Reference A-M, Order Number 253666; Instruction Set Reference N-Z, Order Number 253667; System Programming Guide, Part 1, Order Number 253668; System Programming Guide, Part 2, Order Number 253669. Refer to all five volumes when evaluating your design needs.

The Intel® 64 and IA-32架构软件开发者手册包含了如下五卷:基本架构,顺序号为253665;指令集参考手册A-M,顺序号为253666;指令集参考手册N-Z,顺序号为253667;系统编程指南第一部分,顺序号为253668;系统编程指南第二部分,顺序号为253669。当你评估你的设计需求时可以参考这五卷手册。

注:

1.这里没敢把order number翻译成订单号

2.Refer to all five volumes when evaluating your design needs.这句翻译是否合适,请各位指正。

int __thiscall sub_10001000(_DWORD *this) { _DWORD *v1; // edx signed int v2; // ecx unsigned int v3; // eax int v5; // [esp+0h] [ebp-98h] int v6; // [esp+4h] [ebp-94h] int v7; // [esp+8h] [ebp-90h] int v8; // [esp+Ch] [ebp-8Ch] int v9; // [esp+10h] [ebp-88h] int v10; // [esp+14h] [ebp-84h] int v11; // [esp+18h] [ebp-80h] int v12; // [esp+1Ch] [ebp-7Ch] int v13; // [esp+20h] [ebp-78h] int v14; // [esp+24h] [ebp-74h] int v15; // [esp+28h] [ebp-70h] int v16; // [esp+2Ch] [ebp-6Ch] int v17; // [esp+30h] [ebp-68h] int v18; // [esp+34h] [ebp-64h] int v19; // [esp+38h] [ebp-60h] int v20; // [esp+3Ch] [ebp-5Ch] int v21; // [esp+40h] [ebp-58h] int v22; // [esp+44h] [ebp-54h] int v23; // [esp+48h] [ebp-50h] int v24; // [esp+4Ch] [ebp-4Ch] int v25; // [esp+50h] [ebp-48h] int v26; // [esp+54h] [ebp-44h] int v27; // [esp+58h] [ebp-40h] int v28; // [esp+5Ch] [ebp-3Ch] int v29; // [esp+60h] [ebp-38h] int v30; // [esp+64h] [ebp-34h] int v31; // [esp+68h] [ebp-30h] int v32; // [esp+6Ch] [ebp-2Ch] int v33; // [esp+70h] [ebp-28h] int v34; // [esp+74h] [ebp-24h] int v35; // [esp+78h] [ebp-20h] int v36; // [esp+7Ch] [ebp-1Ch] int v37; // [esp+80h] [ebp-18h] int v38; // [esp+84h] [ebp-14h] int v39; // [esp+88h] [ebp-10h] int v40; // [esp+8Ch] [ebp-Ch] int v41; // [esp+90h] [ebp-8h] __int16 v42; // [esp+94h] [ebp-4h] v1 = this; v5 = 904656733; v2 = 150; v6 = 945984154; v7 = 925490322; v8 = 1975671264; v3 = v1[38]; v9 = -1053814971; if ( v3 < 0x96 ) v2 = v3; v10 = -104732444; v11 = -785623118; v12 = -774160856; v13 = -1651896261; v14 = 2031170445; v15 = 209627365; v16 = 1684532701; v17 = 998187738; v18 = 2036755521; v19 = -87648280; v20 = -1868824629; v21 = 1288876033; v22 = -115946258; v23 = -353948231; v24 = -152286208; v25 = -1064672821; v26 = 1018547391; v27 = 1845933205; v28 = 1963912906; v29 = -907337577; v30 = -1055381981; v31 = 1485485304; v32 = 821575091; v33 = -679865344; v34 = 1247138502; v35 = -1223297121; v36 = -2015505269; v37 = -1661163291; v38 = -675280490; v39 = -561019512; v40 = 473139806; v41 = 158761826; v42 = 17598; return sub_10002B60(v1, &v5, v2); }给你sub_10001000
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