xutian_curry的博客

注意的点是用两个矩阵存放所有房间的状况，每天的传染是只能传染一次的。#include <iostream>#include <string.h>#include <stack>#include <stdio.h>using namespace std;int a[105][105];int b[105][105];stack <i...

小技巧是只用修改状态发生变化的位置。#include <iostream>#include <string>#include <memory.h>using namespace std;int cur[105][105],nxt[105][105];int dx[4] = {1,-1,0,0};int dy[4] = {0,0,1,-1};int ...

吸取下思路#include <iostream>#include <string>#include <memory.h>#include <stdio.h>using namespace std;int row,col;int num[105][105];int main(){ cin >> row >&gt...