HDU5914 Triangle

本文探讨了一道有趣的算法题目——如何通过偷取最少数量的棒子来阻止形成三角形。通过对问题的深入分析,发现其背后的数学规律与斐波那契数列紧密相关,并提供了一种高效的解决方案。

摘要生成于 C知道 ,由 DeepSeek-R1 满血版支持, 前往体验 >

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 502    Accepted Submission(s): 326


Problem Description
Mr. Frog has n sticks, whose lengths are 1,2, 3 n respectively. Wallice is a bad man, so he does not want Mr. Frog to form a triangle with three of the sticks here. He decides to steal some sticks! Output the minimal number of sticks he should steal so that Mr. Frog cannot form a triangle with
any three of the remaining sticks.
 

Input
The first line contains only one integer T ( T20 ), which indicates the number of test cases.

For each test case, there is only one line describing the given integer n ( 1n20 ).
 

Output
For each test case, output one line “Case #x: y”, where x is the case number (starting from 1), y is the minimal number of sticks Wallice should steal.
 

Sample Input
  
3 4 5 6
 

Sample Output
  
Case #1: 1 Case #2: 1 Case #3: 2
 

Source


不翻译了 推了半天发现是斐波拉契数列

#include<bits/stdc++.h>
using namespace std;

int gg[100]={0,0,0,0,1,1,2,3,3,4,5,6,7,7,8,9,10,11,12,13,14};


int main()
{   int t,n;
    scanf("%d",&t);
    for(int h=1;h<=t;h++)
    {   scanf("%d",&n);
        printf("Case #%d: %d\n",h,gg[n]);
    }
    return 0;
}

评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值