数据结构实验之链表七:单链表中重复元素的删除
Time Limit: 1000MS Memory Limit: 65536KB
Submit Statistic
Problem Description
按照数据输入的相反顺序(逆位序)建立一个单链表,并将单链表中重复的元素删除(值相同的元素只保留最后输入的一个)。
Input
第一行输入元素个数 n (1 <= n <= 15);
第二行输入 n 个整数,保证在 int 范围内。
Output
第一行输出初始链表元素个数;
第二行输出按照逆位序所建立的初始链表;
第三行输出删除重复元素后的单链表元素个数;
第四行输出删除重复元素后的单链表。
Example Input
10 21 30 14 55 32 63 11 30 55 30
Example Output
10 30 55 30 11 63 32 55 14 30 21 7 30 55 11 63 32 14 21
01 |
#include
<stdio.h> |
02 |
#include
<stdlib.h> |
03 |
struct node |
04 |
{ |
05 |
int data; |
06 |
struct node
*next; |
07 |
}; |
08 |
int main() |
09 |
{ |
10 |
int n,
i,count; |
11 |
struct node
*p, *tail, *head, *q; |
12 |
head
= ( struct node
*) malloc ( sizeof ( struct node)); |
13 |
head->next
= NULL; |
14 |
scanf ( "%d" ,
&n); |
15 |
tail
= head; |
16 |
for (i
= 0;i<n;i++) |
17 |
{ |
18 |
p
= ( struct node
*) malloc ( sizeof ( struct node)); |
19 |
scanf ( "%d" ,
&p->data); |
20 |
p->next
= tail->next; |
21 |
tail->next
= p; |
22 |
} |
23 |
printf ( "%d\n" ,
n);q = head->next; |
24 |
while (q->next!=NULL) |
25 |
{ |
26 |
printf ( "%d
" ,
q->data); |
27 |
q
= q->next; |
28 |
} |
29 |
printf ( "%d\n" ,
q->data); |
30 |
tail
= head->next; |
31 |
count
= 0; |
32 |
while (tail!=NULL) |
33 |
{ |
34 |
q
= tail;p = tail->next; |
35 |
while (p!=NULL) |
36 |
{ |
37 |
if (p->data==tail->data) |
38 |
{ |
39 |
p
= q->next; |
40 |
q->next
= p->next; |
41 |
free (p); |
42 |
p
= q->next; |
43 |
count++; |
44 |
} |
45 |
else |
46 |
{ |
47 |
q
= q->next;p = q->next; |
48 |
} |
49 |
} |
50 |
tail
= tail->next; |
51 |
} |
52 |
printf ( "%d\n" ,
n-count); |
53 |
tail
= head->next; |
54 |
while (tail->next!=NULL) |
55 |
{ |
56 |
printf ( "%d
" ,
tail->data); |
57 |
tail
=tail->next; |
58 |
} |
59 |
printf ( "%d\n" ,
tail->data); |
60 |
return 0; |
61 |
} |