用下面这个时,就不会出错,但可以达到同样的效果,所以基础的javascript 还是很有用的啊
var tickids = document.getElementsByName("tickid");
for ( var i = 0; i < tickids.length; i++) {tickids[i].checked = this.checked;
}
用下面这个时,就不会出错,但可以达到同样的效果,所以基础的javascript 还是很有用的啊
var tickids = document.getElementsByName("tickid");
for ( var i = 0; i < tickids.length; i++) {