用正则表达式保留系统靓号

最新推荐文章于 2024-09-05 10:05:01 发布

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#正则表达式 #regex #random #string #测试 #手机

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有的时候用户系统用类似于QQ的号码做为UIN，这个时候可能需要保留鞋好的号码供以后不时之需，怎么实现呢？

正则就行了。看代码。

public 
static Dictionary<string, Regex> _validations =
new Dictionary<string, Regex>{
    {"6位顺增号",
new Regex(@"(?:0(?=1)|1(?=2)|2(?=3)|3(?=4)|4(?=5)|5(?=6)|6(?=7)|7(?=8)|8(?=9)){5}\d", RegexOptions.Compiled)},
    {"6位顺降好",
new Regex(@"(?:9(?=8)|8(?=7)|7(?=6)|6(?=5)|5(?=4)|4(?=3)|3(?=2)|2(?=1)|1(?=0)){5}\d", RegexOptions.Compiled)},
    {"6位顺增或顺降号",
new Regex(@"(?:(?:0(?=1)|1(?=2)|2(?=3)|3(?=4)|4(?=5)|5(?=6)|6(?=7)|7(?=8)|8(?=9)){5}|(?:9(?=8)|8(?=7)|7(?=6)|6(?=5)|5(?=4)|4(?=3)|3(?=2)|2(?=1)|1(?=0)){5})\d",
 RegexOptions.Compiled)},
    {"4-9位连续号",new
Regex(@"(?:(?:0(?=1)|1(?=2)|2(?=3)|3(?=4)|4(?=5)|5(?=6)|6(?=7)|7(?=8)|8(?=9)){3,}|(?:9(?=8)|8(?=7)|7(?=6)|6(?=5)|5(?=4)|4(?=3)|3(?=2)|2(?=1)|1(?=0)){3,})\d", RegexOptions.Compiled)},
    {"3位以上重复号",
new Regex(@"([\d])\1{2,}", RegexOptions.Compiled)},
    //{"日期号",new Regex(@"(19|20)[\d]{2}(1[0-2]|0?[1-9])(31|2[0-9]|1[0-9]|0?[0-9])", RegexOptions.Compiled)},
    //{"手机号码号", new Regex(@"(1[3,5,8][0-9]|15[0-9]|18[0-9])([\d]{2,4}){2}", RegexOptions.Compiled)},
    {"AABBB号",
new Regex(@"([\d])\1{1,}([\d])\2{2,}", RegexOptions.Compiled)},
    {"ABBXABB号",
new Regex(@"(([\d]){1,}([\d]){1,})\1{1,}", RegexOptions.Compiled)},
    {"AABBC,ABCDD号",new
Regex(@"([\d])\1{1,}([\d])\2{1,}", RegexOptions.Compiled)},
};
 
public
int GenerateUin()
{
    var r =
new Random((int)DateTime.Now.Ticks);
    var n = r.Next(1000000, 9999999);
    var tmp =
"";
    var t = n.ToString();
 
    if
(!IsGoodUin(t, out
tmp)
        && !ObjectContext.Member.Any(m => m.UIN == t))
        return
n;
 
    return
GenerateUin();                
}
 
public
static bool
IsGoodUin(string
uin, out 
string reason)
{
    var isGood =
false;
    var r1 =
"";
 
    _validations.Each(r =>
    {
        if
(r.Value.IsMatch(uin))
        {
            isGood =
true;
            r1 = r.Key;
            return
false;
        }
 
        return
true;
    });
 
    reason = r1;
    return
isGood;
}

测试以下：

public 
void TestPresentUIN()
{
    100.Each(() =>
    {
        Console.WriteLine(GenerateUin());
    });
}

嗯，输出的号码都是歪瓜裂枣了。呵呵。

转自：http://www.cnblogs.com/nullreference/archive/2010/01/20/keep_present_uin.html

代码