有的时候用户系统用类似于QQ的号码做为UIN,这个时候可能需要保留鞋好的号码供以后不时之需,怎么实现呢?
正则就行了。看代码。
public
static Dictionary< string , Regex> _validations =
new Dictionary< string , Regex>{ { "6位顺增号" ,
new Regex( @"(?:0(?=1)|1(?=2)|2(?=3)|3(?=4)|4(?=5)|5(?=6)|6(?=7)|7(?=8)|8(?=9)){5}\d" , RegexOptions.Compiled)}, { "6位顺降好" ,
new Regex( @"(?:9(?=8)|8(?=7)|7(?=6)|6(?=5)|5(?=4)|4(?=3)|3(?=2)|2(?=1)|1(?=0)){5}\d" , RegexOptions.Compiled)}, { "6位顺增或顺降号" ,
new Regex( @"(?:(?:0(?=1)|1(?=2)|2(?=3)|3(?=4)|4(?=5)|5(?=6)|6(?=7)|7(?=8)|8(?=9)){5}|(?:9(?=8)|8(?=7)|7(?=6)|6(?=5)|5(?=4)|4(?=3)|3(?=2)|2(?=1)|1(?=0)){5})\d" ,
RegexOptions.Compiled)}, { "4-9位连续号" , new
Regex( @"(?:(?:0(?=1)|1(?=2)|2(?=3)|3(?=4)|4(?=5)|5(?=6)|6(?=7)|7(?=8)|8(?=9)){3,}|(?:9(?=8)|8(?=7)|7(?=6)|6(?=5)|5(?=4)|4(?=3)|3(?=2)|2(?=1)|1(?=0)){3,})\d" , RegexOptions.Compiled)}, { "3位以上重复号" ,
new Regex( @"([\d])\1{2,}" , RegexOptions.Compiled)}, //{"日期号",new Regex(@"(19|20)[\d]{2}(1[0-2]|0?[1-9])(31|2[0-9]|1[0-9]|0?[0-9])", RegexOptions.Compiled)}, //{"手机号码号", new Regex(@"(1[3,5,8][0-9]|15[0-9]|18[0-9])([\d]{2,4}){2}", RegexOptions.Compiled)}, { "AABBB号" ,
new Regex( @"([\d])\1{1,}([\d])\2{2,}" , RegexOptions.Compiled)}, { "ABBXABB号" ,
new Regex( @"(([\d]){1,}([\d]){1,})\1{1,}" , RegexOptions.Compiled)}, { "AABBC,ABCDD号" , new
Regex( @"([\d])\1{1,}([\d])\2{1,}" , RegexOptions.Compiled)}, }; public
int GenerateUin() { var r =
new Random(( int )DateTime.Now.Ticks); var n = r.Next(1000000, 9999999); var tmp =
"" ; var t = n.ToString(); if
(!IsGoodUin(t, out
tmp) && !ObjectContext.Member.Any(m => m.UIN == t)) return
n; return
GenerateUin(); } public
static bool
IsGoodUin( string
uin, out
string reason) { var isGood =
false ; var r1 =
"" ; _validations.Each(r => { if
(r.Value.IsMatch(uin)) { isGood =
true ; r1 = r.Key; return
false ; } return
true ; }); reason = r1; return
isGood; } |
测试以下:
public
void TestPresentUIN() { 100.Each(() => { Console.WriteLine(GenerateUin()); }); } |
嗯,输出的号码都是歪瓜裂枣了。呵呵。
转自:http://www.cnblogs.com/nullreference/archive/2010/01/20/keep_present_uin.html

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