J2EE + EXT3.0 用户session 过期处理

最新推荐文章于 2022-08-03 11:57:33 发布

xiayh04

最新推荐文章于 2022-08-03 11:57:33 发布

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CC 4.0 BY-SA版权

文章标签： EXT JSP Ajax

本文链接：https://blog.youkuaiyun.com/xiayh04/article/details/83630715

本文介绍了一种基于Ext.Ajax的前端会话超时处理方法，并通过后端过滤器实现对未登录状态的页面访问控制。具体实现包括前端检测到会话超时后引导用户重新登录，以及后端对特定资源路径的访问权限检查。

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1、前台ext

        Ext.Ajax.on('requestcomplete',function checkUserSessionStatus(conn,response,options){
                //Ext重新封装了response对象
                if(response.getResponseHeader('Timeout') == 'true'){
                //发现请求超时，退出处理代码...
                    Ext.MessageBox.confirm('Confirm', "Your session has time out, please log on again.", function(btn, text){
                                window.location.href="login.jsp";
                                }
                    );
                }
        }, this);

2、后台filter：

public void doFilter(ServletRequest request, ServletResponse response, FilterChain chain) throws IOException, ServletException {
        // pass the request along the filter chain
        logger.info("LoginFiler..beginAdd....");
        HttpServletRequest req = (HttpServletRequest)request;
        HttpServletResponse res = (HttpServletResponse)response;
        String servletPath = req.getServletPath();
        System.out.println("ServletPath: "+req.getServletPath() +" req.getRequestURI(): "+req.getRequestURI() +" getContextPath: "+req.getContextPath());
        if(req.getSession().getAttribute("userInfo")!=null||servletPath.equals("/loginAction.action")||servletPath.equals("/login.jsp"))
        {
            System.out.println("continue....");
            chain.doFilter(request,response) ;
        }
        else if(servletPath.contains(".action"))//
        {
            res.addHeader("Timeout", "true");
            request.getRequestDispatcher("/jsp/common/outOfTime.jsp").forward(req,res);
        }
        else{
            request.getRequestDispatcher("/login.jsp").forward(request,response);
//            res.sendRedirect(req.getContextPath()+"/login.jsp");
        }
    }