修正android 处理连续按键两次

最新推荐文章于 2025-10-05 11:39:28 发布

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本文讨论了按键捕捉的实现方式，并针对原有代码存在的问题进行了改进，同时详细介绍了改进后的Handler对象处理机制。

1.变量初始化：

private  boolean isExit = false;  
private  boolean hasTask = false;

2.按键捕捉（比如放在onTouchDown函数中进行按键监听

PressHomeKeyCount localHandler = new PressHomeKeyCount();
		
	if(isExit == false ) {  
		isExit = true;
		if(!hasTask) {
			Message localMessage = new Message();
			localMessage.what = 0;
			localHandler.sendEmptyMessageDelayed(localMessage.what, 500L);
		}
		else{
			if(mRecentApplication.getVisibility() == View.VISIBLE){
				mRecentApplication.setVisibility(View.INVISIBLE);
				isExit = false;
				hasTask = false;
			}
		}
	}
	else{
		if(mRecentApplication.getVisibility() == View.INVISIBLE){
			mRecentApplication.setVisibility(View.VISIBLE);
		}
	}

3.Handle对象

public class PressHomeKeyCount extends Handler {  
        public void handleMessage(final Message msg) {  
        	isExit = false;    
            	hasTask = true;   
        }  
}

上边的做法会出现死循环，我又对它进行了改进，以下是改进后的代码，经过测试没什么问题，其中变量初始化一样

2.按键捕捉

if(isExit == false ) {    
        isExit = true;  
        if(!hasTask) {  
            Message localMessage = new Message();  
            localMessage.what = 0;  
            localHandler.sendEmptyMessageDelayed(localMessage.what, 500L);  
        }  
        else{  
        	isExit = false;  
            hasTask = false;  
            localHandler.removeMessages(0);

            if(mRecentApplication.getVisibility() == View.VISIBLE){
            	mRecentApplication.setVisibility(View.INVISIBLE);
            }
        } 
    } 
    else{ 
	if(mRecentApplication.getVisibility() == View.INVISIBLE){
		mRecentApplication.setVisibility(View.VISIBLE);
	}
	localHandler.removeMessages(0); 
	isExit = false; 
	hasTask = true; 
    }

3.Handler对象

public class PressHomeKeyCount extends Handler {  
        public void handleMessage(final Message msg) {  
        	isExit = false;    
            	hasTask = false;   
        }  
}