不经保存，直接读取上传文件的内容

最新推荐文章于 2023-04-23 16:29:28 发布

xiaoliangaccp

最新推荐文章于 2023-04-23 16:29:28 发布

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分类专栏： ASP.Net 文章标签： server input asp c# null

本文链接：https://blog.youkuaiyun.com/xiaoliangaccp/article/details/5648124

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本文介绍了一个简单的C#网页应用实例，演示如何在不保存上传文件的情况下直接读取并显示其内容。

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<%@ Page Language="C#" AutoEventWireup="true" %>

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">

<script runat="server">

  protected void btnUpload_Click( object sender, EventArgs e )
  {
    if (FileUpload1.PostedFile.InputStream.Length < 1)
    {
      Msg.Text = "请选择文件。";
      return;
    }
    string FileName = FileUpload1.FileName;
    if (FileName.ToLower().IndexOf(".txt") == -1)
    {
      Msg.Text = "请选择文本文件。";
      return;
    }

    int FileLen = FileUpload1.PostedFile.ContentLength;
    byte[] input = new byte[FileLen];
    System.IO.Stream UpLoadStream = FileUpload1.PostedFile.InputStream;
    UpLoadStream.Read(input, 0, FileLen);
    UpLoadStream.Position = 0;
    System.IO.StreamReader sr = new System.IO.StreamReader(UpLoadStream, System.Text.Encoding.Default);
    Msg.Text = "您上传的文件内容是：<br/><br/>" + sr.ReadToEnd();
    sr.Close();
    UpLoadStream.Close();
    UpLoadStream = null;
    sr = null;
  }
</script>

<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
  <title>不经保存，直接读取上传文件的内容</title>
</head>
<body>
  <form id="MengXianhui" runat="server">
    <asp:FileUpload ID="FileUpload1" runat="server" />
    <asp:Button ID="btnUpload" runat="server" Text="上传" OnClick="btnUpload_Click"></asp:Button>
    <p>
      <asp:Label ID="Msg" runat="server" ForeColor="Red"></asp:Label></p>
  </form>
</body>
</html>