ACM刷题之HDU————Exponentiation

最新推荐文章于 2019-08-20 19:08:51 发布

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最新推荐文章于 2019-08-20 19:08:51 发布

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分类专栏： ACM题目高精度文章标签： ACM BigDecimal java

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本文介绍了一个使用Java实现的大数幂运算方法。通过采用BigDecimal类及其stripTrailingZeros()函数来确保结果精度并去除不必要的尾随零。适用于解决涉及非常大数值的计算问题。

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Exponentiation

Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 2584 Accepted Submission(s): 702

Problem Description

Problems involving the computation of exact values of very large magnitude and precision are common. For example, the computation of the national debt is a taxing experience for many computer systems.

This problem requires that you write a program to compute the exact value of Rⁿ where R is a real number ( 0.0 < R < 99.999 ) and n is an integer such that 0 < n <= 25.

Input

The input will consist of a set of pairs of values for R and n. The R value will occupy columns 1 through 6, and the n value will be in columns 8 and 9.

Output

The output will consist of one line for each line of input giving the exact value of R^n. Leading zeros should be suppressed in the output. Insignificant trailing zeros must not be printed. Don't print the decimal point if the result is an integer.

Sample Input

Sample Output

548815620517731830194541.899025343415715973535967221869852721
.00000005148554641076956121994511276767154838481760200726351203835429763013462401
43992025569.928573701266488041146654993318703707511666295476720493953024
29448126.764121021618164430206909037173276672
90429072743629540498.107596019456651774561044010001
1.126825030131969720661201

大数幂。用JAVA水过

用BigDecimal

根据题意要用stripTrailingZeros()函数去掉多余的0

下面是ac代码

import java.math.BigInteger;
import java.util.Scanner;
import java.math.*;
import java.text.*;
public class Main{

	public static void main(String[] args) {
		// TODO 自动生成的方法存根
		Scanner cin=new Scanner(System.in);
		
		BigDecimal bigDecimal = new BigDecimal("1");
		BigDecimal bigDecimal2 = new BigDecimal("1");
		
		int i = 0,j,k;
		
		while(cin.hasNext())   //等同于!=EOF
		{

			bigDecimal=cin.nextBigDecimal();
			bigDecimal2=bigDecimal;
			i=cin.nextInt();
			
			bigDecimal = bigDecimal.pow(i);
			String string = bigDecimal.stripTrailingZeros().toPlainString();
			
			if(string.startsWith("0."))
				string = string.substring(1);
			
			
			System.out.println(string);
			
		}
	}

}