题目:
Given a binary tree, flatten it to a linked list in-place.
For example,
Given
1 / \ 2 5 / \ \ 3 4 6The flattened tree should look like:
1 \ 2 \ 3 \ 4 \ 5 \ 6
Hints:
If you notice carefully in the flattened tree, each node's right child points to the next node of a pre-order traversal.
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
private TreeNode pre=null;
public void flatten(TreeNode root) {
//递归实现将左右子树变成一个单串
if(root==null) return ;
flatten(root.right);
flatten(root.left);
root.right=pre;
root.left=null;
pre=root;
}
}