“太多的价值无法解包”，遍历一个字典。 键=&gt；字符串，值=&gt；列表

本文翻译自：'too many values to unpack', iterating over a dict. key=>string, value=>list

I am getting the 'too many values to unpack' error. 我收到'too many values to unpack'错误。 Any idea how I can fix this? 知道我该如何解决吗？

first_names = ['foo', 'bar']
last_names = ['gravy', 'snowman']

fields = {
    'first_names': first_names,
    'last_name': last_names,
}        

for field, possible_values in fields:  # error happens on this line              

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#1楼

参考：https://stackoom.com/question/mW7g/太多的价值无法解包-遍历一个字典-键-gt-字符串-值-gt-列表

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#2楼

For Python 3.x iteritems has been removed. 对于Python 3.x， iteritems项目已删除。 Use items instead. 改用物品 。

for field, possible_values in fields.items():
    print(field, possible_values)

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#3楼

For lists, use enumerate 对于列表，请使用enumerate

for field, possible_values in enumerate(fields):
    print(field, possible_values)

iteritems will not work for list objects iteritems不适用于列表对象

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#4楼

Can't be iterating directly in dictionary. 不能直接在字典中进行迭代。 So you can through converting into tuple . 这样就可以通过转换为元组了 。

first_names = ['foo', 'bar']
last_names = ['gravy', 'snowman']

fields = {
    'first_names': first_names,
    'last_name': last_names,
         } 
tup_field=tuple(fields.items())
for names in fields.items():
     field,possible_values = names
     tup_possible_values=tuple(possible_values)
     for pvalue in tup_possible_values:
           print (field + "is" + pvalue)

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#5楼

you are missing fields.iteritems() in your code. 您在代码中缺少fields.iteritems() 。

You could also do it other way, where you get values using keys in the dictionary. 您也可以采用其他方式，即使用字典中的键获取值。

for key in fields:
    value = fields[key]

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#6楼

data = (['President','George','Bush','is','.'],['O','B-PERSON','I-PERSON','O','O'])
corpus = []
for(doc,tags) in data:
    doc_tag = []
    for word,tag in zip(doc,tags):
        doc_tag.append((word,tag))
        corpus.append(doc_tag)
        print(corpus)