如何将传递给我的bash脚本的所有参数传递给我的函数？ [重复]

本文翻译自：How to pass all arguments passed to my bash script to a function of mine? [duplicate]

This question already has answers here : 这个问题已经在这里有了答案 ：

Propagate all arguments in a bash shell script (9 answers) 在bash shell脚本中传播所有参数 （9个答案）

Closed 13 days ago . 13天前关闭。

Let's say I have defined a function abc() that will handle the logic related to analyzing the arguments passed to my script. 假设我已经定义了一个function abc() ，它将处理与分析传递给脚本的参数有关的逻辑。

How can I pass all arguments my bash script has received to it? 如何将bash脚本收到的所有参数传递给它？ The number of params is variable, so I can't just hardcode the arguments passed like this: 参数的数量是可变的，所以我不能仅仅对这样传递的参数进行硬编码：

abc $1 $2 $3 $4

Edit . 编辑 。 Better yet, is there any way for my function to have access to the script arguments' variables? 更好的是，我的函数是否可以访问脚本参数的变量？

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#1楼

参考：https://stackoom.com/question/FzVJ/如何将传递给我的bash脚本的所有参数传递给我的函数-重复

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#2楼

I needed a variation on this, which I expect will be useful to others: 我需要对此进行更改，我希望这对其他人会有用：

function diffs() {
        diff "${@:3}" <(sort "$1") <(sort "$2")
}

The "${@:3}" part means all the members of the array starting at 3. So this function implements a sorted diff by passing the first two arguments to diff through sort and then passing all other arguments to diff, so you can call it similarly to diff: "${@:3}"部分表示从3开始的数组的所有成员。因此，此函数通过将前两个参数传递给diff并随后将所有其他参数传递给diff来实现排序的diff，因此您可以类似于diff来称呼它：

diffs file1 file2 [other diff args, e.g. -y]

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#3楼

It's worth mentioning that you can specify argument ranges with this syntax. 值得一提的是，您可以使用此语法指定参数范围。

function example() {
    echo "line1 ${@:1:1}"; #First argument
    echo "line2 ${@:2:1}"; #Second argument
    echo "line3 ${@:3}"; #Third argument onwards
}

I hadn't seen it mentioned. 我没有看到它提到。

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#4楼

abc "$@"

$@表示提供给bash脚本的所有参数。

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#5楼

使用$@变量，该变量将扩展为所有用空格分隔的命令行参数。

abc "$@"

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#6楼

Here's a simple script: 这是一个简单的脚本：

#!/bin/bash

args=("$@")

echo Number of arguments: $#
echo 1st argument: ${args[0]}
echo 2nd argument: ${args[1]}

$# is the number of arguments received by the script. $#是脚本接收的参数数量。 I find easier to access them using an array: the args=("$@") line puts all the arguments in the args array. 我发现使用数组更容易访问它们： args=("$@")行将所有参数放入args数组中。 To access them use ${args[index]} . 要访问它们，请使用${args[index]} 。