LeetCode单链表相关题在本地执行的方法

步骤:
1)创建ListNode类

class ListNode:
    def __init__(self, x):
        self.val = x
        self.next = None

2)创建单链表类
可参考Python单链表

class SingleLinkList:
    def __init__(self, node=None):
        self.__head = node

    def is_Empty(self):
        return self.__head is None

    def append(self, item): # 尾插法
        node = ListNode(item)
        if self.is_Empty():
            self.__head = node
        else:
            cur = self.__head
            while cur.next is not None: 
                cur = cur.next
            cur.next = node

    def find_head(self):
        return self.__head

3)以 LeetCode 83.删除排序链表中的重复元素为例

class Solution:
    def deleteDuplicates(self, head: ListNode) -> ListNode:
        if head is None or head.next is None:
            return head
        p = head 
        while True:
            if p.val == p.next.val:
                p.next = p.next.next
            else:
                p = p.next
            if p.next is None:
                break
        return head

4)调用
调用方式1

ls = SingleLinkList()
data = [1, 1, 2, 3, 3]
for i in data:
    ls.append(i)
print(type(ls))
mm = Solution()
res = mm.deleteDuplicates(ls.find_head())
while res:
    print(res.val, end=' ')
    res = res.next

调用方式2

mm = Solution()
head = ListNode(None)
cur = head
for i in [1, 1, 2, 3, 3]:
    cur.next = ListNode(i)
    cur = cur.next
head = head.next
print(type(head))
res = mm.deleteDuplicates(head)
while res:
    print(res.val, end=' ')
    res = res.next
评论
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值