在Viewpager的子Activity中startActivityForResult调用其他Activity时候遭遇到onActivityResult方法不响应的问题

最新推荐文章于 2021-04-11 16:49:02 发布

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当在Viewpager内的子Activity使用startActivityForResult启动其他Activity时，可能会遇到onActivityResult回调不触发的问题。解决方法包括在父Activity中初始化子Activity并进行相关设置。

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在Viewpager的子Activity中startActivityForResult调用其他Activity时候遭遇到onActivityResult方法不响应的问题，

解决这个问题的办法如下：

1、先在父Activity里里初始化子Activity

localActivityManager = new LocalActivityManager(this, true);
localActivityManager.dispatchCreate(savedInstanceState);//必须被调用

List<View> viewList = new ArrayList<View>();	    
Intent intent = new Intent(this, SignInActivity.class);
View signInView  =localActivityManager.startActivity("SignInActivity", intent).getDecorView();
viewList.add(signInView);

Intent intent2 = new Intent(this, StatisticsActivity.class);
View statisticsView =localActivityManager.startActivity("StatisticsActivity", intent2).getDecorView();
viewList.add(statisticsView);

ViewPagerAdapter adapter = new ViewPagerAdapter(viewList);
vp_content.setAdapter(adapter);

2、实现父Activity的onActivityResult方法

protected void onActivityResult(int requestCode, int resultCode, Intent data) {
		//Activity activity =localActivityManager.getCurrentActivity();//这里返回的永远是viewpager最后一个activity
		Activity activity =localActivityManager.getActivity("SignInActivity");
		if(activity instanceof SignInActivity){
			SignInActivity signInActivity =(SignInActivity) activity;
			signInActivity.<span style="color:#FF0000;">handleActivityResult</span>(requestCode, resultCode, data);
		}
	};

3、子Activity需要实现handleActivityResult方法

	public void handleActivityResult(int requestCode, int resultCode,
			Intent data) {
		 switch (requestCode) {
			case SCANNIN_GREQUEST_CODE:
				if(resultCode == RESULT_OK){
					Bundle bundle = data.getExtras();
					
					String resultString = bundle.getString("result");
					Log.i("扫一扫", resultString);
					
				}
				break;
			}     
	      super.onActivityResult(requestCode, resultCode, data);
	}