http post方式发送xml格式消息

最新推荐文章于 2022-03-29 15:23:35 发布

转载最新推荐文章于 2022-03-29 15:23:35 发布 · 5.1k 阅读

本文介绍了一个使用Java实现的将XML报文发送到指定URL并接收响应的过程，包括构建XML报文、发送POST请求及解析返回的XML响应。

//返回xml报文

public static String getXml(String userName)
{
StringBuffer sb = new StringBuffer();
sb.append("<?xml version=\"1.0\" encoding=\"UTF-8\"?>");
sb.append("<root>");
sb.append("<stkey>Register</stkey>");
sb.append("<user_id >23l3</user_id>");
sb.append("<login_username>");
sb.append(userName);
sb.append("</login_username>");
sb.append("<client_id>4000df1</client_id>");
sb.append("</root>");
System.out.println("1=====:"+sb.toString());
return sb.toString();
}

public static String sendPost(String postXml)
{
String msg = null ;
try
{
String httpUrl = "http://localhost:8080/MyTest/index.php";
PostMethod postMethod = new PostMethod(httpUrl);

postMethod.setRequestEntity(new StringRequestEntity(postXml, "text/html", "utf-8"));
postMethod.setRequestHeader("Content-type", "text/xml; charset=GBK");

   HttpClient httpClient = new HttpClient();
   httpClient.executeMethod(postMethod);
   int resultint = httpClient.executeMethod(postMethod);
//   log.info("resultint====="+resultint);
//   System.out.println("resultint======="+resultint);

//msg 即为请求返回的消息，这里我们假设请求返回的消息是xml格式，

//那么，msg就是一个xml格式的字符串咯。对于xml格式字符串的解析方法看上一篇日志。
   msg = new String(postMethod.getResponseBody());
//   log.info("msg=========="+msg);
//   System.out.println("mig===="+msg);
   postMethod.releaseConnection();

}catch(Exception ex)
{
   log.info("Post发生异常了"+ex.getMessage());
   System.out.print("exception message:"+ex.getMessage());
   ex.printStackTrace();
   msg = "exception ex" ;
}
return msg;
}

public static void main(String args[])throws Exception
{

String xml = getXml("oosmile");
String str = sendPost(xml);

//str即为返回的xml格式的消息

}