[Lintcode] 搜索旋转排序数组 II Search in Rotated Sorted Array II

跟进“搜索旋转排序数组”，假如有重复元素又将如何？
是否会影响运行时间复杂度？
如何影响？
为何会影响？
写出一个函数判断给定的目标值是否出现在数组中。

样例
给出[3,4,4,5,7,0,1,2]和target=4，返回 true
Follow up for “Search in Rotated Sorted Array”:
What if duplicates are allowed?
Would this affect the run-time complexity? How and why?
Write a function to determine if a given target is in the array.

public class Solution {
    /** 
     * param A : an integer ratated sorted array and duplicates are allowed
     * param target :  an integer to be search
     * return : a boolean 
     */
    public boolean search(int[] A, int target) {
        if(null == A || A.length == 0) return false;
        return search(A, target, 0, A.length-1);
    }

    public boolean search(int[] A, int target, int l, int r) {
        if(l > r) return false;
        while(l<r && A[l] ==A[r]) {
            l++;
        }
        int mid = (l + r)/2;
        if(A[mid] == target) return true;
        if(A[mid] >= A[l]) {
            if(A[mid] >= target && A[l] <= target) {
                return search(A, target, l, mid-1);
            }else {
                return search(A, target, mid+1, r);
            }
        }else{
            if(A[mid] <= target && A[r] >= target) {
                return search(A, target, mid+1, r);
            }else{
                return search(A, target, l, mid-1);
            }
        }
    }
}