Find The Multiple
Time Limit: 1000MS | Memory Limit: 10000K | |||
Total Submissions: 20297 | Accepted: 8236 | Special Judge |
Description
Given a positive integer n, write a program to find out a nonzero multiple m of n whose decimal representation contains only the digits 0 and 1. You may assume that n is not greater than 200 and there is a corresponding m containing no more than 100 decimal
digits.
Input
The input file may contain multiple test cases. Each line contains a value of n (1 <= n <= 200). A line containing a zero terminates the input.
Output
For each value of n in the input print a line containing the corresponding value of m. The decimal representation of m must not contain more than 100 digits. If there are multiple solutions for a given value of n, any one of them is acceptable.
Sample Input
2 6 19 0
Sample Output
10 100100100100100100 111111111111111111
#include <iostream>
#include <stdio.h>
#include <string>
#include <cstring>
#include <algorithm>
#include <cmath>
#include <queue>
#define N 1000009
#define ll __int64
using namespace std;
int n;
int flag;
void dfs(unsigned ll x,int k)//注意使用无符号64位整数
{
if(flag) return;
if(x%n==0)
{
printf("%I64u\n",x);
flag=1;
return;
}
if(k==19) return;//最大19位
dfs(x*10,k+1);
dfs(x*10+1,k+1);
}
int main()
{
while(~scanf("%d",&n))
{
if(n==0) break;
flag=0;
dfs(1,0);
}
return 0;
}