hdu1063 Exponentiation(大整数)-优快云博客

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Exponentiation

Time Limit: 1000/500 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 6509 Accepted Submission(s): 1802

Problem Description

Problems involving the computation of exact values of very large magnitude and precision are common. For example, the computation of the national debt is a taxing experience for many computer systems.

This problem requires that you write a program to compute the exact value of Rⁿ where R is a real number ( 0.0 < R < 99.999 ) and n is an integer such that 0 < n <= 25.

Input

The input will consist of a set of pairs of values for R and n. The R value will occupy columns 1 through 6, and the n value will be in columns 8 and 9.

Output

The output will consist of one line for each line of input giving the exact value of R^n. Leading zeros should be suppressed in the output. Insignificant trailing zeros must not be printed. Don't print the decimal point if the result is an integer.

Sample Input

Sample Output

548815620517731830194541.899025343415715973535967221869852721
.00000005148554641076956121994511276767154838481760200726351203835429763013462401
43992025569.928573701266488041146654993318703707511666295476720493953024
29448126.764121021618164430206909037173276672
90429072743629540498.107596019456651774561044010001
1.126825030131969720661201

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.FileReader;
import java.io.PrintWriter;
import java.io.OutputStreamWriter;
import java.util.StringTokenizer;
import java.io.IOException;
import java.math.BigDecimal;

class Main
{
	public static final boolean DEBUG = false;
	public StringTokenizer tokenizer;
	public PrintWriter cout;
	BufferedReader cin;
	
	public void init() throws IOException
	{		
		if (DEBUG) {
			cin = new BufferedReader(new FileReader("d:\\OJ\\uva_in.txt"));
		} else {
			cin = new BufferedReader(new InputStreamReader(System.in));
		}
		tokenizer = new StringTokenizer("");
		
		cout = new PrintWriter(new OutputStreamWriter(System.out));
	}
	
	public String next() throws IOException
	{
		while (!tokenizer.hasMoreTokens()) {
			String s = cin.readLine();
			if (s == null) return null;
			tokenizer = new StringTokenizer(s);
		}
		
		return tokenizer.nextToken();
	}
	
	public void solve(BigDecimal bd, int n)
	{
		BigDecimal ans = bd.pow(n);
		
		StringBuilder sb = new StringBuilder(ans.toPlainString());
		
		
		if (sb.indexOf(".") != -1) {
			for (int i = sb.length() - 1; i >= 1; i--) {
				if (sb.charAt(i) == '0') {
					sb.deleteCharAt(i);
				} else break;
			}
		}
		
		if (sb.charAt(sb.length() - 1) == '.') sb.deleteCharAt(sb.length() - 1);
		if (sb.indexOf(".") != -1 && sb.charAt(0) == '0') sb.deleteCharAt(0);
		cout.print(sb.toString());
		cout.println();
		cout.flush();
	}
	
	public static void main(String[] args) throws IOException
	{
		Main solver = new Main();
		solver.init();
		String s;
		
		while ((s = solver.next()) != null) {
			BigDecimal bd = new BigDecimal(s);
			int n = Integer.valueOf(solver.next());
			
			solver.solve(bd, n);
		}
		
	}
}