LeetCode 题解｜9. 回文数

/**
 * @param {number} x
 * @return {boolean}
 */
var isPalindrome = function (x) {
  if (x < 0) {
    return false;
  }
  let num = x;
  let reverse = 0;
  while (num != 0) {
    reverse = reverse * 10 + (num % 10);
    num = ~~(num / 10);
  }
  return reverse === x;
};

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