【LeetCode】双链表——设计链表

本文详细介绍了一种双向链表的数据结构设计与实现方法,包括节点的定义、基本操作如插入、删除、获取等,并提供了完整的C++代码实现。通过双向搜索提高查找效率。

链接:https://leetcode-cn.com/explore/learn/card/linked-list/196/doubly-linked-list/759/
在这里插入图片描述
代码:

class MyLinkedList {
struct ListNode{
    int val;
    ListNode *prev,*next;
    ListNode(int val):val(val),prev(NULL),next(NULL){}
};
private:
    ListNode *head;
    ListNode *tail;
    int size;
private:
    ListNode* getNode(int index)//获得目标节点,因为是双向链表,通过判断目标节点位置在前半段还是后半段来决定从head开始搜索还是从tail开始搜索
    {
        if(index<0||index>=size) return NULL;
        ListNode* p;
        if(size/2>index)
        {
            p=head;
            while(index>0)
            {
                p=p->next;
                index--;
            }          
        }
        else
        {
            p=tail;
            while(index<size-1)
            {
                p=p->prev;
                index++;
            }
        }
        return p;
        
    }
public:
    /** Initialize your data structure here. */
    MyLinkedList():head(NULL),tail(NULL),size(0) {}
    
    /** Get the value of the index-th node in the linked list. If the index is invalid, return -1. */
    int get(int index) {
        if(getNode(index)==NULL) return -1;
        else return getNode(index)->val;
    }
    
    /** Add a node of value val before the first element of the linked list. After the insertion, the new node will be the first node of the linked list. */
    void addAtHead(int val) {
        ListNode* node=new ListNode(val);
        size++;
        if(head==NULL)
        {
            head=node;
            tail=node;
        }
        else
        {
            node->next=head;
            head->prev=node;
            head=node;
        }
    }
    
    /** Append a node of value val to the last element of the linked list. */
    void addAtTail(int val) {
        ListNode* node=new ListNode(val);
        size++;
        if(tail==NULL)
        {
            head=node;
            tail=node;
        }
        else
        {
            tail->next=node;
            node->prev=tail;
            tail=node;
        }
    }
    
    /** Add a node of value val before the index-th node in the linked list. If index equals to the length of linked list, the node will be appended to the end of linked list. If index is greater than the length, the node will not be inserted. */
    void addAtIndex(int index, int val) {
        if(index>size) return;
        if(index==size) 
        {
            addAtTail(val);
            return;
        }
        if(index<=0)
        {
            addAtHead(val);
            return;
        }
        ListNode* node=getNode(index);
        ListNode* n=new ListNode(val);
        n->next=node;
        n->prev=node->prev;
        node->prev->next=n;
        node->prev=n;
        size++;
    }
    
    /** Delete the index-th node in the linked list, if the index is valid. */
    void deleteAtIndex(int index) {
        ListNode* node=getNode(index);
        if(node)
        {
            if(node==head)
            {
                head=head->next;
                if(head) head->prev=NULL;
                node->next=NULL;
            }
            if(node==tail)
            {
                tail=tail->prev;
                if(tail) tail->next=NULL;
                node->prev=NULL;
            }
            if(node->next) node->prev->next=node->next;
            if(node->prev) node->next->prev=node->prev;
            delete node;
            size--;
        }
    }
};

/**
 * Your MyLinkedList object will be instantiated and called as such:
 * MyLinkedList* obj = new MyLinkedList();
 * int param_1 = obj->get(index);
 * obj->addAtHead(val);
 * obj->addAtTail(val);
 * obj->addAtIndex(index,val);
 * obj->deleteAtIndex(index);
 */

参考:https://leetcode-cn.com/problems/design-linked-list/solution/cxiang-xi-ti-jie-dai-tu-jie-by-youlookdeliciousc/

评论
成就一亿技术人!
拼手气红包6.0元
还能输入1000个字符
 
红包 添加红包
表情包 插入表情
 条评论被折叠 查看
添加红包

请填写红包祝福语或标题

红包个数最小为10个

红包金额最低5元

当前余额3.43前往充值 >
需支付:10.00
成就一亿技术人!
领取后你会自动成为博主和红包主的粉丝 规则
hope_wisdom
发出的红包
实付
使用余额支付
点击重新获取
扫码支付
钱包余额 0

抵扣说明:

1.余额是钱包充值的虚拟货币,按照1:1的比例进行支付金额的抵扣。
2.余额无法直接购买下载,可以购买VIP、付费专栏及课程。

余额充值