不同类型的不连续的最小值

最新推荐文章于 2022-06-07 15:17:56 发布

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本文通过一个具体的SQL查询案例，展示了如何使用复杂的SQL语句来筛选和处理数据。具体包括创建临时表、插入数据、使用子查询及CTE（公用表表达式）等高级技巧，旨在帮助读者理解并掌握更高效的SQL查询方法。

create table #UU1
(
Num varchar(20)
)
insert into #UU1 select 'a102'
insert into #UU1 select 'a103'
insert into #UU1 select 'a105'
insert into #UU1 select 'a907'
insert into #UU1 select 'a1001'
insert into #UU1 select 'b203'
insert into #UU1 select 'b204'
insert into #UU1 select 'b206'

--1
select *
from #UU1 a
where exists(select 1 from #UU1 where cast(stuff(Num ,1,1,'') as int) = cast(stuff(a.Num ,1,1,'') as int)-1)
and not exists
(select 1 from #UU1 where cast(stuff(Num ,1,1,'') as int) = cast(stuff(a.Num ,1,1,'') as int)+1)

--2

;with hgo as
(
select substring(Num,1,1) num,substring(Num,2,len(num)-1) cnt,
row_number() over(partition by substring(Num,1,1) order by Num asc) as rank
from #UU1
),
h as
(
select * from hgo h where not exists(select * from hgo where num=h.num and rank=h.rank-1 and cnt<>h.cnt-1)
),
g as
(
select num,max(cnt) cnt from h group by num
)
select ltrim(num+ltrim(cnt)) from g