这里提供一个Java实现的HTTP请求代码示例模板:
import java.net.*;
import java.io.*;
public class HttpExample {
// 发送GET请求
public static void sendGet(String url) throws Exception {
URL obj = new URL(url);
HttpURLConnection con = (HttpURLConnection) obj.openConnection();
con.setRequestMethod("GET");
int responseCode = con.getResponseCode();
System.out.println("ResponseCode: " + responseCode);
BufferedReader in = new BufferedReader(
new InputStreamReader(con.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
System.out.println("Response: " + response.toString());
}
// 发送POST请求
public static void sendPost(String url, String data) throws Exception {
URL obj = new URL(url);
HttpURLConnection con = (HttpURLConnection) obj.openConnection();
con.setRequestMethod("POST");
con.setDoOutput(true);
DataOutputStream out = new DataOutputStream(con.getOutputStream());
out.writeBytes(data);
out.flush();
out.close();
int responseCode = con.getResponseCode();
System.out.println("ResponseCode: " + responseCode);
BufferedReader in = new BufferedReader(
new InputStreamReader(con.getInputStream()));
String inputLine;
StringBuffer response = new StringBuffer();
while ((inputLine = in.readLine()) != null) {
response.append(inputLine);
}
in.close();
System.out.println("Response: " + response.toString());
}
public static void main(String[] args) throws Exception{
String url = "https://www.baidu.com";
sendGet(url);
url = "https://example.com/api";
String data = "key1=value1&key2=value2";
sendPost(url, data);
}
}
以上代码实现了一个简单的HTTP请求,包括GET和POST两种方式。其中,GET请求通过创建URL对象和HttpURLConnection对象,并设置请求方法为GET来实现;POST请求则需要设置请求方法为POST,并通过DataOutputStream将POST数据写入请求体中。在请求完成后,获取响应内容需要通过InputStreamReader和BufferedReader来读取响应流并拼接成String。
该代码示例展示了如何使用Java进行HTTP请求,包括GET和POST方法。GET请求通过设置URL和请求方法获取数据,而POST请求需写入请求体并设置请求方法为POST来传递数据。
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