HDU 1144 Prerequisites?

Prerequisites?

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 604    Accepted Submission(s): 385

Problem Description

Freddie the frosh has chosen to take k courses. To meet the degree requirements, he must take courses from each of several categories. Can you assure Freddie that he will graduate, based on his course selection? 

 

Input

Input consists of several test cases. For each case, the first line of input contains 1 ≤ k ≤ 100, the number of courses Freddie has chosen, and 0 ≤ m ≤ 100, the number of categories. One or more lines follow containing k 4-digit integers follow; each is the number of a course selected by Freddie. Each category is represented by a line containing 1 ≤ c ≤ 100, the number of courses in the category, 0 ≤ r ≤ c, the minimum number of courses from the category that must be taken, and the c course numbers in the category. Each course number is a 4-digit integer. The same course may fulfil several category requirements. Freddie's selections, and the course numbers in any particular category, are distinct. A line containing 0 follows the last test case.

 

Output

For each test case, output a line containing "yes" if Freddie's course selection meets the degree requirements; otherwise output "no." 

 

Sample Input

  
  

   
   3 2
0123 9876 2222
2 1 8888 2222
3 2 9876 2222 7654 
3 2
0123 9876 2222
2 2 8888 2222
3 2 7654 9876 2222
0
  
  

 

Sample Output

  
  

   
   yes
no
  
  

 

Source

University of Waterloo Local Contest 2005.09.24

 

Recommend

Eddy

 

分析：题意就是Freddie要选k门课，有m个类别，每个类别有c门课，每个类别最少要选r门课，看每个类别里是否有满足Freddie要选的课而且达到每个类别的选课数目的最低要求，都满足输出yes，否则输出no

代码：

#include<stdio.h>
#include<string.h>

int main()
{
    char a[110][10];
    char b[110][10];
    int k,m,c,r;
    while(scanf("%d",&k))
    {
        if(k==0)
            break;
        scanf("%d",&m);
        getchar();
        int i,j,n,flag=0;
        for(i=0;i<k;i++)
            scanf("%s",a[i]);
        for(i=0;i<m;i++)
        {
            int count=0;
            scanf("%d%d",&c,&r);
            getchar();
            for(j=0;j<c;j++)
                scanf("%s",b[j]);
            for(n=0;n<k;n++)
            {
                for(j=0;j<c;j++)
                {
                    if(strcmp(a[n],b[j])==0)
                        count++;
                }
            }
            if(count>=r)
                flag++;
        }
        if(flag==m)
            printf("yes\n");
        else
            printf("no\n");
    }
    return 0;
}