ZOJ 2099 Frame Polygonal Line

Frame Polygonal Line

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Time Limit: 2 Seconds      Memory Limit: 65536 KB

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You are going to read a sequence of pairs of integer numbers. Each pair represents the Cartesian coordinates of a point in a 2-dimentional plane. The first number is the x coordinate, while the second is that of y. The sequence represents a polygonal line. Your task is to draw a rectangle with minimal length of sides that exactly surrounds the polygonal line. The sides of the rectangle are parallel to x- and y-axis, respectively.

Input

Input consists of several test cases. For each case, a sequence of coordinates is given. Each pair of x and y occupies a line, with |x| and |y| less than 2^31. The sequence is terminated with a pair of 0's. Note that (0, 0) will never be considered as a point on any of the polygonal lines. An empty polygonal line signals the end of input.

Output

For each test case, print in one line two pairs of numbers, which are the south-west and north-east corners of the surrounding rectangle. The numbers must be separated by one space as is indicated in the samples.

Sample Input

12 56
23 56
13 10
0 0
12 34
0 0
0 0

Sample Output

12 10 23 56
12 34 12 34

题意：本题就是求把这个多边形围起来的矩形的周长最小的矩形坐标。就是求x,y的最小值和x.y的最大值

代码：

#include <stdio.h>


int main()
{
    int x,y;
    while(scanf("%d%d",&x,&y))
    {
        if(x==0&&y==0)
            break;
        int minx,miny,maxx,maxy;
        minx=maxx=x;
        miny=maxy=y;
        while(1)
        {
            scanf("%d%d",&x,&y);
            if(x==0&&y==0)
                break;
            if(x<minx)
                minx=x;
            if(x>maxx)
                maxx=x;
            if(y<miny)
                miny=y;
            if(y>maxy)
                maxy=y;
        }
        printf("%d %d %d %d\n",minx,miny,maxx,maxy);
    }
    return 0;
}