两个N*N矩阵的乘法，矩阵由一维数组表示-优快云博客

本文提供了两个用于计算二维矩阵乘法的C语言函数。这两个函数分别适用于行优先存储和列优先存储的一维数组表示的矩阵。通过具体示例展示了如何使用这些函数进行矩阵运算。

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#include <math.h>
#include <stdio.h>

/*This function will calculate two dimensional matrixes' product.
* Please note, they are represented as one-dimensional arrays.
* Note:
* Only apply to line-storage matrix.
*/
void multiply(int result[], int a[], int b[], int n) {
    int i=0;
    int count=pow(n, 2);
    for (i=0; i<count; i++) {
        /* 1 = 4/3 */
        int row = i / n;
        int column = i % n;
        int k;
        result[i]=0;
        for (k=0; k < n; k++) {
            result[i] += a[row*n + k] * b[column + k*n];
        }
    }

}

/*This function will calculate two dimensional matrixes' product.
* Please note, they are represented as one-dimensional arrays.
* Note:
* Only apply to column-storage matrix.
*/
void multiply2(int result[], int a[], int b[], int n) {
    int i=0;
    int count=pow(n, 2);
    for (i=0; i<count; i++) {
        /* 1 = 4/3 */
        int row = i % n;
        int column = i / n;
        int k;
        result[i]=0;
        for (k=0; k < n; k++) {
            result[i] += a[row + k*n] * b[column*n + k];
        }
    }

}

main() {
    int A[9]={1, 1, 1, 1, 1, 1, 1, 1, 1};
    int B[9]={1, 1, 1, 1, 1, 1, 1, 1, 1};
    int C[9];
    int i;
    multiply(&C, A, B, 3);
    for (i=0; i < 9; i++) {
        printf("%d ", C[i]);
    }

    printf("/n");

    multiply2(&C, A, B, 3);
    for (i=0; i < 9; i++) {
        printf("%d ", C[i]);
    }
    getch();
}