Python 以一个指定的间隔定时循环执行任务

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最新推荐文章于 2025-07-01 16:34:23 发布

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本文介绍了一个简单的Python定时任务调度器实现。该调度器允许用户指定一个或多个固定的时间间隔（如分钟、小时、天等），并据此周期性地执行特定的任务函数。文中提供了一个具体的例子，展示如何设置每天加两天小时后再加一分钟时执行一次任务。

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http://www.linuxidc.com/Linux/2014-03/97555.htm

程序功能：指定一个或者同时多个固定的延迟（例如，5mins, 1hour,1 day, 1 week）,程序按照这个指定的延迟定时循环执行某个work

from datetime import date, time, datetime, timedelta

def work():
  print "hello world."


def runTask(func, day=0, hour=0, min=0, second=0):
  # Init time
  now = datetime.now()
  strnow = now.strftime('%Y-%m-%d %H:%M:%S')
  print "now:",strnow
  # First next run time
  period = timedelta(days=day, hours=hour, minutes=min, seconds=second)
  next_time = now + period
  strnext_time = next_time.strftime('%Y-%m-%d %H:%M:%S')
  print "next run:",strnext_time
  while True:
      # Get system current time
      iter_now = datetime.now()
      iter_now_time = iter_now.strftime('%Y-%m-%d %H:%M:%S')
      if str(iter_now_time) == str(strnext_time):
          # Get every start work time
          print "start work: %s" % iter_now_time
          # Call task func
          func()
          print "task done."
          # Get next iteration time
          iter_time = iter_now + period
          strnext_time = iter_time.strftime('%Y-%m-%d %H:%M:%S')
          print "next_iter: %s" % strnext_time
          # Continue next iteration
          continue

# runTask(work, min=0.5)
runTask(work, day=1, hour=2, min=1)