WC 2011 xor

这篇题解我是来除草的。。。具体题解请见莫涛神犇的题解。。。以及APIO上他的讲题

#include<cstdio>
#include<cstdlib>
#include<cmath>
#include<cstring>
int n=0,m=0,e=1,maxt=0,s=0;
long long sum[50005],x=0,a[100005],choose=0,w[200005];
int head[50005],link[200005],next[200005];
bool vis[50005],flag[200005];
void add(int u,int v,long long tmpw)
{
  next[++e]=head[u];
  head[u]=e;
  link[e]=v;
  w[e]=tmpw;
  next[++e]=head[v];
  head[v]=e;
  link[e]=u;
  w[e]=tmpw;
}
void dfs(int s)
{
  vis[s]=1;
  for (int ne=head[s];ne;ne=next[ne])
    if (!vis[link[ne]])
      {
	flag[ne]=1;
	flag[ne^1]=1;
	sum[link[ne]]=sum[s]^w[ne];
	dfs(link[ne]);
      }
}
void update(int &a,int b)
{
  if (a<b) a=b;
}
int main()
{
  freopen("xor.in","r",stdin);
  freopen("xor.out","w",stdout);
  scanf("%d%d",&n,&m);
  int i=0,j=0,u=0,v=0;
  long long tmpw=0;
  for (i=1;i<=m;i++)
    {
      scanf("%d%d%I64d",&u,&v,&tmpw);
      add(u,v,tmpw);
    }
  sum[1]=0;
  dfs(1);
  for (i=2;i<=e;i++)
    if (!flag[i])
      {
	a[++s]=sum[link[i]]^sum[link[i^1]]^w[i];
	flag[i]=1;flag[i^1]=1;
	update(maxt,(int)(log2(a[s])+1));
      }
  x=sum[n];
  update(maxt,(int)(log2(a[s])+1));
  for (i=maxt-1;i>=0;i--)
    {
      choose=0;
      for (j=1;j<=s;j++)
	if (a[j]&(long long)((long long)(1)<<(long long)(i)))
	  {
	    choose=a[j];
	    break;
	  }
      if (choose)
	{
	  if ((x&(long long)((long long)(1)<<(long long)(i)))==0) x^=choose;
	  for (j=1;j<=s;j++)
	    if (a[j]&(long long)((long long)(1)<<(long long)(i)))
	      a[j]^=choose;
	}
    }
  printf("%I64d",x);
  return 0;
}


以下代码在radasm编译后打开.exe无法生成窗口_ProcWinMain proc uses ebx esi edi hWnd,wMsg,wParam,lParam LOCAL @stPs:PAINTSTRUCT LOCAL @hDc mov eax,wMsg .if eax==WM_CREATE mov Score,0 mov PlayFlag,1 mov Velocity,400 invoke LoadIcon,hInstance,ID_ICO invoke SendMessage,hWnd,WM_SETICON,ICON_BIG,eax .elseif .else invoke DefWindowProc,hWnd,wMsg,wParam,lParam ret .endif xor eax,eax ret _ProcWinMain endp ;******************************************************************** ;创建窗口 ;******************************************************************** WinMain proc hInst:HINSTANCE,hPrevInst:HINSTANCE,CmdLine:LPSTR,CmdShow:DWORD LOCAL @wc:WNDCLASSEX LOCAL @msg:MSG LOCAL @hwnd:HWND mov @wc.cbSize,sizeof WNDCLASSEX mov @wc.style,CS_HREDRAW or CS_VREDRAW mov @wc.lpfnWndProc,offset _ProcWinMain mov @wc.cbClsExtra,NULL mov @wc.cbWndExtra,NULL push hInstance pop @wc.hInstance invoke LoadMenu,hInstance,IDR_MENU mov hMenu,eax mov @wc.hbrBackground,COLOR_BTNFACE+1 mov @wc.lpszMenuName,NULL mov @wc.lpszClassName,offset ClassName invoke LoadIcon,hInstance,ID_ICO mov @wc.hIcon,eax mov @wc.hIconSm,eax invoke LoadCursor,NULL,IDC_ARROW mov @wc.hCursor,eax invoke RegisterClassEx,addr @wc invoke CreateWindowEx,WS_EX_CLIENTEDGE or WS_EX_WINDOWEDGE,\ addr ClassName,addr AppName,\ WS_MINIMIZEBOX or WS_SYSMENU,\ CW_USEDEFAULT,CW_USEDEFAULT,\ 132h,179h,NULL,hMenu,hInst,NULL mov @hwnd,eax invoke ShowWindow,@hwnd,CmdShow invoke UpdateWindow,@hwnd .while TRUE invoke GetMessage,addr @msg,NULL,0,0 .break .if(!eax) invoke TranslateMessage,addr @msg invoke DispatchMessage,addr @msg .endw mov eax,@msg.wParam ret WinMain endp start: invoke GetModuleHandle,NULL mov hInstance,eax invoke WinMain,hInstance,NULL,CommandLine,SW_SHOWDEFAULT invoke ExitProcess,eax end start
最新发布
03-27
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