搭建struts框架

最新推荐文章于 2019-03-11 13:46:11 发布

原创最新推荐文章于 2019-03-11 13:46:11 发布 · 217 阅读

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CC 4.0 BY-SA版权

文章标签：

#struts #myeclipse

本文详细介绍如何在MyEclipse中搭建Struts2框架环境，包括项目创建、配置web.xml及struts.xml文件、实现简单的注册功能等步骤。

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环境：myeclipse下

新建一个webproject

框架：

1.导包

2.配置WebRoot下的lib文件里面的web.xml(配置过滤器）

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">
  <display-name>com.csdn.struts</display-name>
  <filter>
    <filter-name>struts2</filter-name>
    <filter-class>org.apache.struts2.dispatcher.FilterDispatcher</filter-class>
  </filter>
  <filter-mapping>
    <filter-name>struts2</filter-name>
    <url-pattern>/*</url-pattern>//这里最好是/* 也可以是.action 
  </filter-mapping>
  <welcome-file-list>
    <welcome-file>index.jsp</welcome-file>
  </welcome-file-list>
</web-app>

3.在src下面新建一个实体类RegAction.java WebRoot下面新建一个reg.jsp.

(生成get set方法可以在工具栏里面点击Source,里面有generate getters and setters；生成构造方法也有)

RegAction.java

import com.opensymphony.xwork2.ActionSupport;

public class RegAction extends ActionSupport {
private String username;
private String password;
private String phone;

@Override
public String execute() throws Exception {
	System.out.print(username+"==="+password+"==="+phone);
	return "index";
}

public String getUsername() {
	return username;
}

public void setUsername(String username) {
	this.username = username;
}

public String getPassword() {
	return password;
}
public void setPassword(String password) {
	this.password = password;
}
public String getPhone() {
	return phone;
}
public void setPhone(String phone) {
	this.phone = phone;
}

}

reg.jsp
<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%>
<%
String path = request.getContextPath();
String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";
%>
<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN">
<html>
  <head>
    <base href="<%=basePath%>">  
    <title>My JSP 'reg.jsp' starting page</title>
	<meta http-equiv="pragma" content="no-cache">
	<meta http-equiv="cache-control" content="no-cache">
	<meta http-equiv="expires" content="0">    
	<meta http-equiv="keywords" content="keyword1,keyword2,keyword3">
	<meta http-equiv="description" content="This is my page">
	<!--
	<link rel="stylesheet" type="text/css" href="styles.css">
	-->
  </head>

  <body>
   <form method="post" action="regAction">//这里的regAction一定要和struts.xml里面的action name一致，表单提交的内容才会给相应的Action处理
   姓名：<input type="text" name="username" /><br/>//这里的username要和RegAction里面的属性username一直，否则值也传不到类里面去
   密码：<input type="password" name="password"><br/>
   电话：<input type="text" name="phone"><br>
   <input type="submit" value="注册">
   </form>
  </body>
</html>

4.新建一个struts.xml文件

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE struts PUBLIC "-//Apache Software Foundation//DTD Struts Configuration 2.1//EN" "http://struts.apache.org/dtds/struts-2.1.dtd">
<struts>
<package name="base" extends="struts-default">
<action name="regAction" class="com.xzz.action.RegAction">
	<result name="index">index.jsp</result>//这里可以跳转到任何页面，我这里只是跳转到index页面
</action>
</package>
</struts>

5.运行