剑指offer--链表中倒数第k个结点

题目描述

输入一个链表，输出该链表中倒数第k个结点。

/*
struct ListNode {
	int val;
	struct ListNode *next;
	ListNode(int x) :
			val(x), next(NULL) {
	}
};*/
class Solution {
public:
    ListNode* FindKthToTail(ListNode* pListHead, unsigned int k) {
        if(pListHead == NULL || k == 0)
            return NULL;
        ListNode* n1 = pListHead;
        int i;
        for(i = 0; i < k; i++)
            if(n1)n1 = n1->next;
            else break;
        if(i != k)return   NULL;
        ListNode* n2 = pListHead;
        while(n1){
            n1 = n1->next;
            n2 = n2->next;
        }
        return n2;
    }
};