该博客探讨了一种常见编程问题，即判断二叉树中是否存在一条从根节点到叶子节点的路径，其节点值之和等于给定的目标值。博主介绍了两种解决方案：递归和广度优先搜索（BFS）。递归方法通过不断减去当前节点值，直到找到目标路径或返回false。BFS版本则利用队列存储节点及其路径和，逐个检查路径。三种实现方式（递归、栈、队列）都被展示并分析，有助于读者理解和掌握这些算法。
Given the root of a binary tree and an integer targetSum, return true if the tree has a root-to-leaf path such that adding up all the values along the path equals targetSum.
A leaf is a node with no children.
Example 1:
Input: root = [5,4,8,11,null,13,4,7,2,null,null,null,1], targetSum = 22
Output: true
Explanation: The root-to-leaf path with the target sum is shown.
Example 2:
Input: root = [1,2,3], targetSum = 5
Output: false
Explanation: There two root-to-leaf paths in the tree:
(1 --> 2): The sum is 3.
(1 --> 3): The sum is 4.
There is no root-to-leaf path with sum = 5.
Example
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